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0.30g of an organic compound C,H,O on combustion yield 0.44g of CO2 and 0.18g H2O.If one mole of compound weigh 60,then molecular formula of compound is,?
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0.30g of an organic compound C,H,O on combustion yield 0.44g of CO2 an...
Given Information:
- Mass of organic compound = 0.30g
- Mass of CO2 produced = 0.44g
- Mass of H2O produced = 0.18g
- Molar mass of the compound = 60g/mol
Calculating Moles:
To determine the molecular formula of the compound, we need to calculate the number of moles of carbon, hydrogen, and oxygen present in the given masses of CO2 and H2O.
Step 1: Moles of CO2
The molar mass of CO2 is 44g/mol. We can use this information to calculate the number of moles of CO2 produced.
Moles of CO2 = Mass of CO2 / Molar mass of CO2
Moles of CO2 = 0.44g / 44g/mol
Moles of CO2 = 0.01 mol
Step 2: Moles of H2O
The molar mass of H2O is 18g/mol. We can use this information to calculate the number of moles of H2O produced.
Moles of H2O = Mass of H2O / Molar mass of H2O
Moles of H2O = 0.18g / 18g/mol
Moles of H2O = 0.01 mol
Step 3: Moles of Carbon
In one mole of CO2, there is one mole of carbon. Therefore, the number of moles of carbon is equal to the number of moles of CO2.
Moles of carbon = Moles of CO2
Moles of carbon = 0.01 mol
Step 4: Moles of Hydrogen
In one mole of H2O, there are two moles of hydrogen. Therefore, the number of moles of hydrogen is twice the number of moles of H2O.
Moles of hydrogen = 2 * Moles of H2O
Moles of hydrogen = 2 * 0.01 mol
Moles of hydrogen = 0.02 mol
Step 5: Moles of Oxygen
To find the number of moles of oxygen, we can subtract the moles of carbon and hydrogen from the total moles of the compound.
Moles of oxygen = Total moles - Moles of carbon - Moles of hydrogen
Moles of oxygen = 1 - 0.01 mol - 0.02 mol
Moles of oxygen = 0.97 mol
Calculating Empirical Formula:
Now that we have the moles of carbon, hydrogen, and oxygen, we can calculate the empirical formula of the compound.
Step 1: Convert Moles to Simplest Whole Number Ratio
To find the simplest whole number ratio, we divide the number of moles by the smallest number of moles obtained.
Moles of carbon = 0.01 mol / 0.01 mol = 1
Moles of hydrogen = 0.02 mol / 0.01 mol = 2
Moles of oxygen = 0.97 mol / 0.01 mol = 97
The simplest whole number ratio is 1:2:97.
- Mass of organic compound = 0.30g
- Mass of CO2 produced = 0.44g
- Mass of H2O produced = 0.18g
- Molar mass of the compound = 60g/mol
Calculating Moles:
To determine the molecular formula of the compound, we need to calculate the number of moles of carbon, hydrogen, and oxygen present in the given masses of CO2 and H2O.
Step 1: Moles of CO2
The molar mass of CO2 is 44g/mol. We can use this information to calculate the number of moles of CO2 produced.
Moles of CO2 = Mass of CO2 / Molar mass of CO2
Moles of CO2 = 0.44g / 44g/mol
Moles of CO2 = 0.01 mol
Step 2: Moles of H2O
The molar mass of H2O is 18g/mol. We can use this information to calculate the number of moles of H2O produced.
Moles of H2O = Mass of H2O / Molar mass of H2O
Moles of H2O = 0.18g / 18g/mol
Moles of H2O = 0.01 mol
Step 3: Moles of Carbon
In one mole of CO2, there is one mole of carbon. Therefore, the number of moles of carbon is equal to the number of moles of CO2.
Moles of carbon = Moles of CO2
Moles of carbon = 0.01 mol
Step 4: Moles of Hydrogen
In one mole of H2O, there are two moles of hydrogen. Therefore, the number of moles of hydrogen is twice the number of moles of H2O.
Moles of hydrogen = 2 * Moles of H2O
Moles of hydrogen = 2 * 0.01 mol
Moles of hydrogen = 0.02 mol
Step 5: Moles of Oxygen
To find the number of moles of oxygen, we can subtract the moles of carbon and hydrogen from the total moles of the compound.
Moles of oxygen = Total moles - Moles of carbon - Moles of hydrogen
Moles of oxygen = 1 - 0.01 mol - 0.02 mol
Moles of oxygen = 0.97 mol
Calculating Empirical Formula:
Now that we have the moles of carbon, hydrogen, and oxygen, we can calculate the empirical formula of the compound.
Step 1: Convert Moles to Simplest Whole Number Ratio
To find the simplest whole number ratio, we divide the number of moles by the smallest number of moles obtained.
Moles of carbon = 0.01 mol / 0.01 mol = 1
Moles of hydrogen = 0.02 mol / 0.01 mol = 2
Moles of oxygen = 0.97 mol / 0.01 mol = 97
The simplest whole number ratio is 1:2:97.
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0.30g of an organic compound C,H,O on combustion yield 0.44g of CO2 an...
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0.30g of an organic compound C,H,O on combustion yield 0.44g of CO2 and 0.18g H2O.If one mole of compound weigh 60,then molecular formula of compound is,?
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0.30g of an organic compound C,H,O on combustion yield 0.44g of CO2 and 0.18g H2O.If one mole of compound weigh 60,then molecular formula of compound is,? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 0.30g of an organic compound C,H,O on combustion yield 0.44g of CO2 and 0.18g H2O.If one mole of compound weigh 60,then molecular formula of compound is,? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.30g of an organic compound C,H,O on combustion yield 0.44g of CO2 and 0.18g H2O.If one mole of compound weigh 60,then molecular formula of compound is,?.
0.30g of an organic compound C,H,O on combustion yield 0.44g of CO2 and 0.18g H2O.If one mole of compound weigh 60,then molecular formula of compound is,? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 0.30g of an organic compound C,H,O on combustion yield 0.44g of CO2 and 0.18g H2O.If one mole of compound weigh 60,then molecular formula of compound is,? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.30g of an organic compound C,H,O on combustion yield 0.44g of CO2 and 0.18g H2O.If one mole of compound weigh 60,then molecular formula of compound is,?.
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