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The probability that a non leap year selected at random will have 53 Sundays is
- a)1/7
- b)2/7
- c)3/7
- d)4/7
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The probability that a non leap year selected at random will have 53 S...
Non-leap year contains 365 days = 52 weeks + 1 days
52 weeks contain 52 Sundays
We will get 53 Sundays if one Sunday will come in a week.
Number of Total possible outcomes = 7
Number of possible outcomes = 1
∴ Required Probability = 1/7
52 weeks contain 52 Sundays
We will get 53 Sundays if one Sunday will come in a week.
Number of Total possible outcomes = 7
Number of possible outcomes = 1
∴ Required Probability = 1/7
Most Upvoted Answer
The probability that a non leap year selected at random will have 53 S...
Because in a non leap year 365 days exit so there 52 Monday+ 1 days that is probability is 1/7
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The probability that a non leap year selected at random will have 53 S...
Introduction:
A non-leap year consists of 365 days, which is divided into 52 weeks and 1 extra day. In a non-leap year, each day of the week occurs 52 times, except for one day which occurs 53 times. We need to find the probability of this extra day being a Sunday.
Analysis:
Let's analyze the problem step by step:
1. Total number of days in a non-leap year: 365 days.
2. Total number of weeks in a non-leap year: 52 weeks.
3. Total number of days in 52 weeks: 52 x 7 = 364 days.
4. Remaining days after 52 weeks: 365 - 364 = 1 day.
Probability Calculation:
To find the probability, we need to determine the number of favorable outcomes and the total number of possible outcomes.
1. Number of favorable outcomes: The extra day can be Sunday, which is only one day of the week.
2. Total number of possible outcomes: There are 7 days in a week.
Therefore, the probability of the extra day being a Sunday is 1 out of 7, which can be written as 1/7.
Conclusion:
The probability that a non-leap year selected at random will have 53 Sundays is 1/7. This means that in a non-leap year, there is a 1/7 chance that the extra day will be a Sunday.
A non-leap year consists of 365 days, which is divided into 52 weeks and 1 extra day. In a non-leap year, each day of the week occurs 52 times, except for one day which occurs 53 times. We need to find the probability of this extra day being a Sunday.
Analysis:
Let's analyze the problem step by step:
1. Total number of days in a non-leap year: 365 days.
2. Total number of weeks in a non-leap year: 52 weeks.
3. Total number of days in 52 weeks: 52 x 7 = 364 days.
4. Remaining days after 52 weeks: 365 - 364 = 1 day.
Probability Calculation:
To find the probability, we need to determine the number of favorable outcomes and the total number of possible outcomes.
1. Number of favorable outcomes: The extra day can be Sunday, which is only one day of the week.
2. Total number of possible outcomes: There are 7 days in a week.
Therefore, the probability of the extra day being a Sunday is 1 out of 7, which can be written as 1/7.
Conclusion:
The probability that a non-leap year selected at random will have 53 Sundays is 1/7. This means that in a non-leap year, there is a 1/7 chance that the extra day will be a Sunday.
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The probability that a non leap year selected at random will have 53 Sundays isa)1/7b)2/7c)3/7d)4/7Correct answer is option 'A'. Can you explain this answer?
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The probability that a non leap year selected at random will have 53 Sundays isa)1/7b)2/7c)3/7d)4/7Correct answer is option 'A'. Can you explain this answer? for Class 10 2025 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about The probability that a non leap year selected at random will have 53 Sundays isa)1/7b)2/7c)3/7d)4/7Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 10 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The probability that a non leap year selected at random will have 53 Sundays isa)1/7b)2/7c)3/7d)4/7Correct answer is option 'A'. Can you explain this answer?.
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