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The best method for the conversion of an alcohol into an alkyl chloride is by treating the alcohol with
  • a)
    SOCl2 in presence of pyridine
  • b)
    PCl5
  • c)
    Dry HCl in the presence of anhydrous ZnCl2
  • d)
    PCl3
Correct answer is option 'A'. Can you explain this answer?
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Conversion of alcohol into alkyl chloride using SOCl2 in the presence of pyridine

Alcohols can be converted into alkyl chlorides through a substitution reaction where the hydroxyl group (-OH) of the alcohol is replaced by a chlorine atom (-Cl). One of the most effective methods for this conversion is by treating the alcohol with thionyl chloride (SOCl2) in the presence of pyridine. This method is commonly known as the "Swern oxidation" or the "Dowd-Beckwith method".

Reaction mechanism:

The reaction proceeds through the following steps:

1. Formation of an alkyl chlorosulfite intermediate: The alcohol reacts with thionyl chloride (SOCl2) to form an alkyl chlorosulfite intermediate. This step involves the nucleophilic attack of the oxygen atom of the alcohol on the sulfur atom of SOCl2, resulting in the formation of an alkyl chlorosulfite. This reaction is facilitated by the presence of pyridine, which acts as a base to neutralize the hydrogen chloride (HCl) produced during the reaction.

2. Elimination of sulfur dioxide: The alkyl chlorosulfite intermediate undergoes elimination of sulfur dioxide (SO2) to form the alkyl chloride. This step involves the intramolecular displacement of the chlorine atom by the oxygen atom of the chlorosulfite group, resulting in the formation of a sulfite ester intermediate. This intermediate is unstable and decomposes to release sulfur dioxide, leaving behind the desired alkyl chloride.

3. Regeneration of pyridine: The pyridine, which was initially used as a base, gets protonated during the reaction and forms pyridinium chloride. This pyridinium chloride is then deprotonated by the alkoxide ion formed in the first step, regenerating the pyridine and completing the catalytic cycle.

Advantages of using SOCl2 in the presence of pyridine:

- High yield: This method offers high conversion yields, ensuring efficient conversion of alcohols into alkyl chlorides.
- Selectivity: The reaction primarily targets the hydroxyl group of the alcohol, resulting in the substitution of the -OH group with a chlorine atom (-Cl) without affecting other functional groups present in the molecule.
- Mild reaction conditions: The reaction can be carried out at room temperature, making it convenient and cost-effective.
- Wide applicability: This method is applicable to a wide range of alcohols, including primary, secondary, and tertiary alcohols.

In conclusion, treating an alcohol with thionyl chloride (SOCl2) in the presence of pyridine is the best method for the conversion of an alcohol into an alkyl chloride. This method offers high conversion yields, selectivity, and can be carried out under mild reaction conditions.
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The best method for the conversion of an alcohol into an alkyl chloride is by treating the alcohol witha)SOCl2 in presence of pyridineb)PCl5c)Dry HCl in the presence of anhydrousZnCl2d)PCl3Correct answer is option 'A'. Can you explain this answer?
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