Manik walks 4m towards east then turn to his right and walks 4m and th...
Problem:
Manik walks 4m towards east then turn to his right and walks 4m and then turns to his left and walks 5m. Again turning to his left he walks 4m and stops. What is the shortest distance between the starting point and ending point?
Solution:
Let’s assume that Manik starts from point A and ends at point B. We need to find the shortest distance between points A and B.
From the given information, we can draw the following diagram:
```
|
| 4m
|
--------A---------
4m | 5m
|
|
| 4m
```
Now, let’s find the coordinates of points A and B.
Starting point (A) is (0,0).
After walking 4m towards east, Manik is at point P which is (4,0).
After turning right and walking 4m, Manik is at point Q which is (4,4).
After turning left and walking 5m, Manik is at point R which is (-1,4).
After turning left again and walking 4m, Manik reaches point B which is (-1,0).
Now, we have the coordinates of points A and B. We can use the distance formula to find the distance between them.
Distance formula: d = sqrt((x2-x1)^2 + (y2-y1)^2)
d = sqrt((-1-0)^2 + (0-4)^2)
d = sqrt(1+16)
d = sqrt(17)
d ≈ 4.12m
Therefore, the shortest distance between the starting point and ending point is approximately 4.12m. So, option (c) is the correct answer.
Manik walks 4m towards east then turn to his right and walks 4m and th...
A man walks 4 m towards east and then, turas bo to the worth of east and again walks for calculate the net displacement