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In Δ ABC, ∠A + ∠B = 65°, ∠B + ∠C = 140°, then find ∠B.
- a)40°
- b)25°
- c)35°
- d)20°
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
In Δ ABC, ∠A + ∠B = 65°, ∠B + ∠C = 140°,...
We know that the sum of angles of a triangle is 180°.
∴ ∠A + ∠B + ∠C = 180°
Given: ∠A + ∠B = 65°
Replacing this value we get,
⇒ 65 + ∠C = 180
⇒∠C = 115°
Also, ∠B + ∠C = 140° (given)
⇒∠B + 115° = 140°
∴ ∠B = 25°
∴ ∠A + ∠B + ∠C = 180°
Given: ∠A + ∠B = 65°
Replacing this value we get,
⇒ 65 + ∠C = 180
⇒∠C = 115°
Also, ∠B + ∠C = 140° (given)
⇒∠B + 115° = 140°
∴ ∠B = 25°
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In Δ ABC, ∠A + ∠B = 65°, ∠B + ∠C = 140°,...
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In Δ ABC, ∠A + ∠B = 65°, ∠B + ∠C = 140°, then find ∠B.a)40°b)25°c)35°d)20°Correct answer is option 'B'. Can you explain this answer?
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