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The side AC of the ΔABC is produced to D, such that CD = CB. If ∠ACB = 70°, then the value of ∠ADB is
  • a)
    35°
  • b)
    40°
  • c)
    45°
  • d)
    55°
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The side AC of the ΔABC is produced to D, such that CD = CB. If ...

Now we see that Δ ADB is isosceles as CD = CB and the sum of ∠ CBD and ∠ CDB is 70° (exterior angle property of a triangle). So,
∠CBD = ∠CDB    (isosceles triangle)
∠CBD + ∠CDB = 70°
⇒ 2 × ∠CDB = 70°
⇒ ∠ CDB = 35°
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Most Upvoted Answer
The side AC of the ΔABC is produced to D, such that CD = CB. If ...
Shape is not specified, so it is impossible to determine the length of side AC without additional information.
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The side AC of the ΔABC is produced to D, such that CD = CB. If ∠ACB = 70°, then the value of ∠ADB isa)35°b)40°c)45°d)55°Correct answer is option 'A'. Can you explain this answer?
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