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Sin232° + sin258° + cot258° is equal to
  • a)
    cosec232°cot258°
  • b)
    sin232°cot258°
  • c)
    sin258°cot258°
  • d)
    sin232°tan258°
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Sin232° + sin258° + cot258° is equal toa)cosec232°cot2...
Sinθ = cos(90° - θ) and sin2θ + cos2θ = 1 and Sec2θ = 1 + tan2θ
Sin232° + sin258° + cot258°
= sin232° + cos232° + cot258°
= 1 + cot258°
= cosec258°

= cot258°/cos258°
= cot258°/sin232°
= cosec232°cot258°
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Sin232° + sin258° + cot258° is equal toa)cosec232°cot258°b)sin232°cot258°c)sin258°cot258°d)sin232°tan258°Correct answer is option 'A'. Can you explain this answer?
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