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From each corner of a square of side 4 cm, a quadrant of a circle of radius 1 cm is cut and also a circle of diameter 2 cm is cut as shown is figure. The area of the remaining (shaded) portion is
  • a)
    (16 – 2π) cm2
  • b)
    (16 – 5π) cm2
  • c)
    2π cm2
  • d)
    5π cm2
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
From each corner of a square of side 4 cm, a quadrant of a circle of r...
Area of a square = side × side
Area of a circle = πr2,
Area of quadrant of a circle = πr2/4
Where r is radius.
Given, from each corner of a square of side 4 cm, a quadrant of a circle of radius 1 cm is cut and also a circle of diameter 2 cm is cut.
Area of the Whole square = Side2 = (4 cm)2 = 16 cm2
Area of circle and quadrants (radius = 1 cm) = π r+ [4 × (π r2/4)]
= π (1 cm)2 + [π (1 cm)2]
= 2π
Shaded Area = [16 – 2π] cm2
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From each corner of a square of side 4 cm, a quadrant of a circle of radius 1 cm is cut and also a circle of diameter 2 cm is cut as shown is figure. The area of the remaining (shaded) portion isa)(16 – 2π) cm2b)(16 – 5π) cm2c)2π cm2d)5π cm2Correct answer is option 'A'. Can you explain this answer?
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