in a random mating population frequency of dominant allele is 0.7. wha...
The basic formulas: p^2+2pq+q^2=1 and p+q = 1 where:p = frequency of the dominant allele in the populationq = frequency of the recessive allele in the populationp^2= frequency of homozygous dominant individualsq^2= frequencyof homozygous recessive individuals2pq = frequencyof heterozygous individuals Thus, frequency of recessive allele: q = 1−p = 1−0.7=0.3.Frequency of recessive phenotype: q^2=0.3^2=0.09
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in a random mating population frequency of dominant allele is 0.7. wha...
the total frequency for an allele is 1, so it is 0.3 for the recessive allele.put the dominant frequency in place of 'a' and recessive frequency in place of 'b'.Refer to evolution ncert book. Hardy Weinberg principle.
in a random mating population frequency of dominant allele is 0.7. wha...
Frequency of Dominant Allele in a Random Mating Population
In a random mating population, the frequency of a dominant allele is given as 0.7. This means that out of all the alleles present in the population, 70% of them are dominant alleles.
Frequency of Recessive Phenotype
To determine the frequency of the recessive phenotype, we need to consider the genotype frequencies in the population. The frequency of the recessive phenotype can be calculated using the Hardy-Weinberg equilibrium equation.
The Hardy-Weinberg equation is represented as follows:
p^2 + 2pq + q^2 = 1
Where:
- p^2 represents the frequency of the homozygous dominant genotype (AA)
- 2pq represents the frequency of the heterozygous genotype (Aa)
- q^2 represents the frequency of the homozygous recessive genotype (aa)
Calculating the Frequency of the Homozygous Dominant Genotype (AA)
The frequency of the homozygous dominant genotype (AA) can be calculated by taking the square of the frequency of the dominant allele. In this case, the frequency of the dominant allele is given as 0.7. Thus, the frequency of the homozygous dominant genotype is:
p^2 = (0.7)^2 = 0.49
Calculating the Frequency of the Heterozygous Genotype (Aa)
The frequency of the heterozygous genotype (Aa) can be calculated by multiplying the frequencies of the dominant and recessive alleles and then multiplying the result by 2. Since the frequency of the dominant allele is given as 0.7, the frequency of the recessive allele can be calculated as:
q = 1 - p = 1 - 0.7 = 0.3
Thus, the frequency of the heterozygous genotype is:
2pq = 2 * 0.7 * 0.3 = 0.42
Calculating the Frequency of the Homozygous Recessive Genotype (aa)
The frequency of the homozygous recessive genotype (aa) can be calculated by taking the square of the frequency of the recessive allele. In this case, the frequency of the recessive allele is 0.3. Thus, the frequency of the homozygous recessive genotype is:
q^2 = (0.3)^2 = 0.09
Calculating the Frequency of the Recessive Phenotype
The frequency of the recessive phenotype can be obtained by adding the frequencies of the homozygous recessive genotype and the heterozygous genotype:
Frequency of recessive phenotype = q^2 + 2pq = 0.09 + 0.42 = 0.51
Therefore, the frequency of the recessive phenotype in the random mating population with a dominant allele frequency of 0.7 is 0.51, or 51%.
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