A can contains a mixture of milk and water in the ratio of 4 : 1. When...
Given,
If capacity of can is 5a then milk is 4a and water is a.
Given,
After 15 litres mixture drawn off
⇒ Milk amount = 4a – 4/5 × 15 = 4a – 12
⇒ Water amount = a – 1/5 × 15 + 15 = a + 12
Given,
⇒ (4a – 12) : (a + 12) = 17 : 8
⇒ 32a – 96 = 17a + 204
⇒ 15a = 300
⇒ a = 20
∴ Total mixture = 5 × 20 = 100 litre
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A can contains a mixture of milk and water in the ratio of 4 : 1. When...
Given information:
- The ratio of milk to water in the can is 4:1.
- When 15 litres of the mixture is drawn off and replaced with water, the ratio becomes 17:8.
Let's solve the problem step by step:
Step 1: Initial mixture
- Let's assume the initial mixture in the can contains 4x litres of milk and x litres of water.
- Therefore, the total quantity of the initial mixture = 4x + x = 5x litres.
Step 2: After drawing off 15 litres
- When 15 litres of the mixture is drawn off, the quantity of milk remaining = 4x - (15/5) = 4x - 3 litres.
- The quantity of water remaining = x - (15/5) = x - 3 litres.
Step 3: After filling with water
- After drawing off 15 litres, the can is filled with water.
- Therefore, the quantity of milk remains the same, i.e., 4x - 3 litres.
- The quantity of water is now x - 3 + 15 = x + 12 litres.
Step 4: New ratio
- The new ratio of milk to water is given as 17:8.
- Therefore, (4x - 3)/(x + 12) = 17/8.
Step 5: Solving the equation
- Cross-multiplying, we get 8(4x - 3) = 17(x + 12).
- Simplifying further, we have 32x - 24 = 17x + 204.
- Combining like terms, we get 15x = 228.
- Dividing both sides by 15, we get x = 15.2.
Step 6: Total mixture the can can hold
- The total quantity of the mixture the can can hold = 5x = 5 * 15.2 = 76 litres.
Therefore, the correct answer is option A) 100 litres.