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If x + y = √3 and x - y = √2, then the value of (x2 + y2) is
- a)3
- b)√6/2
- c)5/2
- d)√5/2
Correct answer is option 'C'. Can you explain this answer?
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If x + y = √3 and x - y = √2, then the value of (x2+ ...
From the given data
We know that x + y = √3 and x - y = √2
By adding both the equations, we get
⇒ 2x = √ 3 + √ 2
⇒ x = (√ 3 + √ 2 )/2
Substitute x = (√3 + √2)/2 in x + y = √3
⇒ y = [2√3 - (√3 + √2)]/2 = (√3 –√2 )/2
Substitute x = (√3 + √2)/2 and y = (√3 - √2)/2 in (x2 + y2)
⇒ (x2 + y2) = [{ (√3 + √2)/2 }2 + {(√3 - √2)/2 }2]
= [2(3 + 2)]/4
= 5/2
We know that x + y = √3 and x - y = √2
By adding both the equations, we get
⇒ 2x = √ 3 + √ 2
⇒ x = (√ 3 + √ 2 )/2
Substitute x = (√3 + √2)/2 in x + y = √3
⇒ y = [2√3 - (√3 + √2)]/2 = (√3 –√2 )/2
Substitute x = (√3 + √2)/2 and y = (√3 - √2)/2 in (x2 + y2)
⇒ (x2 + y2) = [{ (√3 + √2)/2 }2 + {(√3 - √2)/2 }2]
= [2(3 + 2)]/4
= 5/2
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If x + y = √3 and x - y = √2, then the value of (x2+ y2) isa)3b)√6/2c)5/2d)√5/2Correct answer is option 'C'. Can you explain this answer?
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