Jugnu, a dishonest milk seller has certain quantity of milk to sell. F...
Let the cost price of 100 g milk was 100 units.
Let’s assume that x grams of milk are mixed with (100 – x) grams of water.
x + 5% of x = 100
⇒ x + 0.05x = 100
⇒ 1.05x = 100
⇒ x = 100/1.05 = 2000/21
Water = 100 – (2000/21) = 100/21
Ratio of water and Milk = 100/2000 = 1 : 20
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Jugnu, a dishonest milk seller has certain quantity of milk to sell. F...
Problem Analysis:
Let's assume that Jugnu has x liters of milk. To gain a profit of 5% by selling the mixture at the cost price, Jugnu needs to mix water in such a way that the cost price of the mixture is the same as the cost price of the original milk.
Solution:
To solve this problem, we can use the concept of the cost price.
Step 1: Determine the initial cost price of the milk:
As the cost price of the milk is the same as the cost price of the mixture, we can assume the initial cost price of the milk to be 100.
Step 2: Determine the selling price of the mixture:
Since Jugnu wants to gain a profit of 5% by selling the mixture at the cost price, the selling price of the mixture will also be 100.
Step 3: Determine the cost price of the mixture:
As the selling price of the mixture is 100, and the profit is 5%, the cost price of the mixture can be calculated using the formula:
Cost Price = Selling Price / (1 + Profit %)
Cost Price = 100 / (1 + 5/100)
Cost Price = 100 / (1 + 0.05)
Cost Price = 100 / 1.05
Cost Price ≈ 95.238
Step 4: Determine the quantity of water to be mixed:
Let's assume that the quantity of water to be mixed is y liters.
The cost price of 1 liter of milk = 100 / x
The cost price of 1 liter of water = 0
The cost price of 1 liter of the mixture = 95.238 / (x + y)
To maintain the cost price, the ratio of milk to water should be equal to the ratio of their cost prices.
Therefore, (100 / x) : 0 = 95.238 / (x + y) : y
Simplifying the equation, we get:
100 / x = 95.238 / (x + y)
Cross-multiplying, we get:
100(x + y) = 95.238x
100x + 100y = 95.238x
100y = 95.238x - 100x
100y = -4.762x
y = (-4.762x) / 100
y = -0.04762x
This equation represents the ratio of milk to water.
Step 5: Approximating the ratio:
Given the options, we need to find the approximate ratio of milk to water.
The ratio y : x can be approximated to 1 : 20.
Therefore, the approximate ratio of milk to water is 1 : 20.
Hence, the correct answer is option D) 1 : 20.