If the diagonals of a rhombus are 24 and 10, then the value of thrice ...
Half of each of the two diagonal forms the two sides of a right - angled triangle whose hypotenuse is the side of the rhombus.
Length of Diagonal 1 = 24
Length of Diagonal 2 = 10
⇒ Sides of the triangle = 12 and 5
Since it’s a right - angled triangle, it should follow Pythagoras theorem.
⇒ (Side)2 = (12)2 + (5)2
⇒ Side = 13
∴ Side of the rhombus = 13.
⇒ Thrice the value of the side = 3 × 13 = 39
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If the diagonals of a rhombus are 24 and 10, then the value of thrice ...
Given: Diagonals of a rhombus = 24 and 10
To find: Thrice the side of the rhombus
Formula: In a rhombus, diagonals are perpendicular bisectors of each other and bisect the angles into two equal parts.
Therefore, let's draw a rhombus and label the diagonals as AB and CD, where AB = 24 and CD = 10.
![Rhombus](https://cdn1.byjus.com/wp-content/uploads/2018/02/rhombus.png)
Let's draw the perpendicular bisectors of AB and CD and mark the intersection as E.
![Rhombus with perpendicular bisectors](https://cdn1.byjus.com/wp-content/uploads/2018/02/rhombus-1.png)
Let's mark the side of the rhombus as x. As per the formula, AE = BE = AB/2 = 24/2 = 12 and CE = DE = CD/2 = 10/2 = 5.
![Rhombus with perpendicular bisectors and side](https://cdn1.byjus.com/wp-content/uploads/2018/02/rhombus-2.png)
Now, let's apply the Pythagoras theorem in triangles AEC and BED to find the value of x.
In triangle AEC, AC^2 = AE^2 + EC^2
=> AC^2 = 12^2 + x^2
In triangle BED, BD^2 = BE^2 + ED^2
=> BD^2 = 12^2 + x^2
As per the formula, AC = BD = diagonal of a rhombus
=> 24^2 + x^2 = 10^2 + x^2
=> 576 = 100
This is not possible. Hence, the given values of the diagonals cannot form a rhombus.
Therefore, the answer to the question is "Data inadequate" or "Not possible to form a rhombus with given diagonal lengths."