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Initial velocity of a particle moving along is(20 -2)m/sec if it's acceleration is a=(5 -0.1) then velocity of a particle with error after t=(10 -1)?
Most Upvoted Answer
Initial velocity of a particle moving along is(20 -2)m/sec if it's acc...
U=(20-2) a= (5+0.1) t=(10+1)
final velocity of partical
v=u+at
v=20+5×10=70 m/s
error
du=+-2 dt=+-1 da=+-0.1
dv/dx=du/dx+dat/dx
dv/dx= du/dx+ tda/dx+adt/dx
dv=du+tda+adt
dv=2+10×0.1+5×1
2+1+5=8m/s
v+dv=70+-8m/s
final velocity of partical
v=u+at
v=20+5×10=70 m/s
error
du=+-2 dt=+-1 da=+-0.1
dv/dx=du/dx+dat/dx
dv/dx= du/dx+ tda/dx+adt/dx
dv=du+tda+adt
dv=2+10×0.1+5×1
2+1+5=8m/s
v+dv=70+-8m/s
Community Answer
Initial velocity of a particle moving along is(20 -2)m/sec if it's acc...
Given:
Initial velocity, u = (20 - 2) m/s
Acceleration, a = (5 - 0.1) m/s^2
Time, t = (10 - 1) s
Finding:
Velocity of the particle with error after time t
Solution:
We can use the kinematic equation to find the velocity of the particle with error after time t.
v = u + at
Let's calculate the value of v with error.
v = (20 - 2) + (5 - 0.1) × (10 - 1)
v = 18 + 4.9 × 9
v = 63.1 m/s
Now, let's calculate the absolute and relative error in the velocity.
Absolute error = Actual value - Approximate value
Absolute error in v = |63.1 - 63| = 0.1 m/s
Relative error = (Absolute error / Actual value) × 100
Relative error in v = (0.1 / 63) × 100 = 0.16%
Answer:
The velocity of the particle with error after time t is 63.1 m/s. The absolute error in the velocity is 0.1 m/s and the relative error is 0.16%.
Initial velocity, u = (20 - 2) m/s
Acceleration, a = (5 - 0.1) m/s^2
Time, t = (10 - 1) s
Finding:
Velocity of the particle with error after time t
Solution:
We can use the kinematic equation to find the velocity of the particle with error after time t.
v = u + at
Let's calculate the value of v with error.
v = (20 - 2) + (5 - 0.1) × (10 - 1)
v = 18 + 4.9 × 9
v = 63.1 m/s
Now, let's calculate the absolute and relative error in the velocity.
Absolute error = Actual value - Approximate value
Absolute error in v = |63.1 - 63| = 0.1 m/s
Relative error = (Absolute error / Actual value) × 100
Relative error in v = (0.1 / 63) × 100 = 0.16%
Answer:
The velocity of the particle with error after time t is 63.1 m/s. The absolute error in the velocity is 0.1 m/s and the relative error is 0.16%.
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Initial velocity of a particle moving along is(20 -2)m/sec if it's acceleration is a=(5 -0.1) then velocity of a particle with error after t=(10 -1)?
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Initial velocity of a particle moving along is(20 -2)m/sec if it's acceleration is a=(5 -0.1) then velocity of a particle with error after t=(10 -1)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Initial velocity of a particle moving along is(20 -2)m/sec if it's acceleration is a=(5 -0.1) then velocity of a particle with error after t=(10 -1)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Initial velocity of a particle moving along is(20 -2)m/sec if it's acceleration is a=(5 -0.1) then velocity of a particle with error after t=(10 -1)?.
Initial velocity of a particle moving along is(20 -2)m/sec if it's acceleration is a=(5 -0.1) then velocity of a particle with error after t=(10 -1)? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Initial velocity of a particle moving along is(20 -2)m/sec if it's acceleration is a=(5 -0.1) then velocity of a particle with error after t=(10 -1)? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Initial velocity of a particle moving along is(20 -2)m/sec if it's acceleration is a=(5 -0.1) then velocity of a particle with error after t=(10 -1)?.
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