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A stone thrown vertically upward files past a window one second after it was thrown upward and after three second on its way downward.The height of the window above the ground is?
Most Upvoted Answer
A stone thrown vertically upward files past a window one second after ...
Given data:
- Time taken to pass the window on the way up: 1 second
- Time taken to pass the window on the way down: 3 seconds

Calculating the height of the window:
- Let's consider the stone's initial velocity as 'u' when it was thrown vertically upward from the ground.
- When the stone reaches the window after 1 second on the way up, its velocity would be 'v' and it would have traveled a certain distance 's1'.
- Using the equation of motion: s1 = ut + (1/2)at^2, where a is the acceleration due to gravity (-9.8 m/s^2), we can find 's1'.
- After 3 seconds on its way down, the stone reaches the window again. This time its velocity would be '-u' as it's moving downward. Let's denote the distance traveled on the way down as 's2'.
- Using the same equation of motion: s2 = ut + (1/2)at^2, we can find 's2'.
- The total height of the window above the ground can be calculated by adding 's1' and 's2'.

Final Answer:
- By calculating 's1' and 's2' and adding them together, we can determine the height of the window above the ground where the stone passes by.
Community Answer
A stone thrown vertically upward files past a window one second after ...
H = g t1 t2 /2 ->10×1×3÷2=15 let me know if ans is correct
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A stone thrown vertically upward files past a window one second after it was thrown upward and after three second on its way downward.The height of the window above the ground is?
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