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Benzoic acid undergoes dimerisation in benzene solution. The Vant's Hoff factor 'i' is related to the degree of dissociation 'α' of the acid as
  • a)
    i =(1- α)
  • b)
    i =1 + α
  • c)
    i =(1- α/2)
  • d)
    i =(1 + α/2)
Correct answer is option 'C'. Can you explain this answer?
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The Vant Hoff factor (i) is related to the degree of dissociation (α) by the equation:

i = 1 + (n-1)α

where n is the number of particles formed when the compound dissociates.

In the case of benzoic acid dimerization, the compound dissociates into two particles (monomers) and forms a dimer. So, n = 2.

If the degree of dissociation of benzoic acid is α, then the Vant Hoff factor (i) can be calculated using the above equation as:

i = 1 + (2-1)α
i = 1 + α

Therefore, the Vant Hoff factor (i) is equal to 1 plus the degree of dissociation (α) for benzoic acid dimerization in benzene solution.
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Benzoic acid undergoes dimerisation in benzene solution. The Vant's Hoff factor 'i' is related to the degree of dissociation 'α' of the acid asa)i =(1- α)b)i =1 + αc)i =(1- α/2)d)i =(1 + α/2)Correct answer is option 'C'. Can you explain this answer?
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Benzoic acid undergoes dimerisation in benzene solution. The Vant's Hoff factor 'i' is related to the degree of dissociation 'α' of the acid asa)i =(1- α)b)i =1 + αc)i =(1- α/2)d)i =(1 + α/2)Correct answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Benzoic acid undergoes dimerisation in benzene solution. The Vant's Hoff factor 'i' is related to the degree of dissociation 'α' of the acid asa)i =(1- α)b)i =1 + αc)i =(1- α/2)d)i =(1 + α/2)Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Benzoic acid undergoes dimerisation in benzene solution. The Vant's Hoff factor 'i' is related to the degree of dissociation 'α' of the acid asa)i =(1- α)b)i =1 + αc)i =(1- α/2)d)i =(1 + α/2)Correct answer is option 'C'. Can you explain this answer?.
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