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Calculate the relative permeability of material having magnetization of 3400 ampere/meter and flux density of 0.0045 wb/m2.
- a)20.25
- b)9.82
- c)19.68
- d)13.25
Correct answer is option 'C'. Can you explain this answer?
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To calculate the relative permeability of a material, we need to use the formula:
μr = B / (μ0 * H)
where,
μr = relative permeability
B = flux density in Weber per square meter (Wb/m^2)
μ0 = permeability of free space or vacuum (4π * 10^-7 H/m)
H = magnetization in Amperes per meter (A/m)
Given:
Magnetization (H) = 3400 A/m
Flux density (B) = 0.0045 Wb/m^2
Using the given values in the formula, we can calculate the relative permeability:
μr = 0.0045 / (4π * 10^-7 * 3400)
Simplifying further:
μr = 0.0045 / (4 * 3.14 * 10^-7 * 3400)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 19.68
Therefore, the relative permeability of the material is approximately 19.68. Hence, option C is the correct answer.
μr = B / (μ0 * H)
where,
μr = relative permeability
B = flux density in Weber per square meter (Wb/m^2)
μ0 = permeability of free space or vacuum (4π * 10^-7 H/m)
H = magnetization in Amperes per meter (A/m)
Given:
Magnetization (H) = 3400 A/m
Flux density (B) = 0.0045 Wb/m^2
Using the given values in the formula, we can calculate the relative permeability:
μr = 0.0045 / (4π * 10^-7 * 3400)
Simplifying further:
μr = 0.0045 / (4 * 3.14 * 10^-7 * 3400)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 0.0045 / (4 * 3.14 * 3.4 * 10^-4)
μr ≈ 19.68
Therefore, the relative permeability of the material is approximately 19.68. Hence, option C is the correct answer.
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Calculate the relative permeability of material having magnetization of 3400 ampere/meter and flux density of 0.0045 wb/m2.a)20.25b)9.82c)19.68d)13.25Correct answer is option 'C'. Can you explain this answer?
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