A train covers a distance between two stations P and Q in 30 minutes. If the speed of the train is reduced by 10km/hr, then the same distance is covered in 45 minutes. The distance between P and Qa)10kmb)15kmc)20kmd)30kme)None of theseCorrect answer is option 'B'. Can you explain this answer?

Question

Answer

D = S*1/2 and D = (S-10)*3/4
solve both equation. u will get D = 15km

Answer

Given information:
- The train covers a distance between stations P and Q in 30 minutes.
- When the speed of the train is reduced by 10 km/hr, the same distance is covered in 45 minutes.

To find: The distance between stations P and Q.

Let's assume the original speed of the train is V km/hr.

1. Calculating the distance covered in 30 minutes:
- Speed = Distance/Time
- Distance = Speed * Time
- Distance = V * (30/60) [Converting 30 minutes to hours]
- Distance = V/2

2. Calculating the distance covered in 45 minutes after reducing the speed by 10 km/hr:
- New speed = V - 10 km/hr
- Distance = Speed * Time
- Distance = (V - 10) * (45/60) [Converting 45 minutes to hours]
- Distance = (V - 10) * 3/4

According to the given information, the distances covered in 30 minutes and 45 minutes are the same. Therefore, we can equate the two distances:

V/2 = (V - 10) * 3/4

Simplifying the equation:

4V = 6V - 60
2V = 60
V = 30

Hence, the original speed of the train is 30 km/hr.

3. Calculating the distance between stations P and Q:
- Distance = V * (30/60)
- Distance = 30 * 0.5
- Distance = 15 km

Therefore, the distance between stations P and Q is 15 km.

Hence, the correct answer is option B) 15 km.

Answer

Let speed =S km/hr, time taken = 30min=1/2hr
distance(T*S)= S/2 km;
similarly , new speed =(S-10) km/hr
new time =45/60= 3/4hrs;
distance =(S-10)3/4;
Distance is equal , (S-10)3/4= S/2;
so, S= 30 km/hr;
now distance = 30/2 = 15km op(B)

Answer

D = S*1/2 and D = (S-10)*3/4
solve both equation. u will get D = 15km

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