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What will be the work done when one mole of a gas expands isothermally from 15 L to 50L against a constant pressure of 1 atm at 25 degree celsius? a) -718 cal b) -843. 3 cal c) -60. 23 cal?
Most Upvoted Answer
What will be the work done when one mole of a gas expands isothermally...


Given data:
- Initial volume (Vi) = 15 L
- Final volume (Vf) = 50 L
- Pressure (P) = 1 atm
- Temperature (T) = 25°C

Formula to calculate work done in an isothermal process:
- Work done (W) = -nRT ln(Vf/Vi)
- Where n = number of moles, R = gas constant, T = temperature in Kelvin, Vi = initial volume, Vf = final volume

Calculations:
- Convert temperature to Kelvin: T = 25°C + 273 = 298 K
- Number of moles (n) = 1 mole
- Gas constant (R) = 0.0821 atm L/mol K

Substitute the values in the formula:
- W = -1 * 0.0821 * 298 * ln(50/15) = -843.3 cal

Therefore, the work done when one mole of gas expands isothermally from 15 L to 50 L against a constant pressure of 1 atm at 25°C is -843.3 cal. Hence, the correct answer is b) -843.3 cal.
Community Answer
What will be the work done when one mole of a gas expands isothermally...
Use equation 
 w= -2.303 n r t log {v2/V1}
after putting values you will get i as 718 cal

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What will be the work done when one mole of a gas expands isothermally from 15 L to 50L against a constant pressure of 1 atm at 25 degree celsius? a) -718 cal b) -843. 3 cal c) -60. 23 cal?
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