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Steam enters a well insulated turbine and expands isentropically throughout. At an intermediate pressure, 20 percent of the mass is extracted for process heating and the remaining steam expands isentropically to 9 kPa.
Inlet to turbine: P = 14 MPa, T = 560°C, h = 3486 kJ/kg, s = 6.6 kJ/(kg.K)
Intermediate stage: h = 27776 kJ/kg
Exit of turbine: P = 9 kPa, hf = 174 kJ/kg, hg = 2574 kJ/kg,
sf = 0.6 kJ/(kg.K), sg = 8.1 kJ/(kg.K)
If the flow rate of steam entering the turbine is 100 kg/s, then the work output (in MW) is _______.
(Important - Enter only the numerical value in the answer)
    Correct answer is '125.56'. Can you explain this answer?
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    To solve this problem, we can use the steam tables to find the properties of steam at each stage of the process.

    Given:
    Inlet to turbine:
    P1 = 14 MPa
    T1 = 560 °C

    Intermediate Pressure:
    P2 = ?
    m2 = 20% of mass

    Outlet Pressure:
    P3 = 9 kPa

    Using the steam tables, we can find the specific enthalpy and entropy values for the given conditions.

    At the inlet to the turbine (state 1):
    h1 = 3426.2 kJ/kg
    s1 = 6.8839 kJ/kg·K

    At the intermediate pressure (state 2):
    s2 = s1 (isentropic expansion)
    h2 = h1 - (h1 - hf2) * (m2 / m1) (mass extraction)

    To find h2, we need to find hf2 (enthalpy of saturated liquid) at state 2. We can use the steam tables to find the hf2 value at the intermediate pressure P2.

    At the outlet pressure (state 3):
    s3 = s2 (isentropic expansion)
    h3 = hf3 + (s3 - sf3) * (hfg3 / sfg3) (enthalpy calculation using saturated liquid and vapor values)

    To find h3, we need to find hf3 (enthalpy of saturated liquid) and hfg3 (enthalpy of vaporization) at state 3. We can use the steam tables to find these values at the outlet pressure P3.

    Once we have h2 and h3, we can calculate the work done by the turbine using the equation:

    Work = m1 * (h1 - h2) + (m1 - m2) * (h2 - h3)

    Note: The mass flow rate m1 is not given in the problem, so we cannot calculate the actual numerical value of the work done. The given information is sufficient to calculate the work per unit mass (specific work) or to compare the work done at different conditions.
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    Steam enters a well insulated turbine and expands isentropically throughout. At anintermediate pressure, 20 percent of the mass is extracted for process heating and theremaining steam expands isentropically to 9 kPa.Inlet to turbine: P = 14 MPa, T = 560°C, h = 3486 kJ/kg, s = 6.6 kJ/(kg.K)Intermediate stage: h = 27776 kJ/kgExit of turbine: P = 9 kPa, hf = 174 kJ/kg, hg = 2574 kJ/kg,sf = 0.6 kJ/(kg.K), sg = 8.1 kJ/(kg.K)If the flow rate of steam entering the turbine is 100 kg/s, then the work output (in MW) is_______.(Important - Enter only the numerical value in the answer)Correct answer is '125.56'. Can you explain this answer?
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