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To code 50 amino in a polypeptide chain what will be the minimum number. of nucleotide in cistron?
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To code 50 amino in a polypeptide chain what will be the minimum numbe...
Minimum Number of Nucleotides in a Cistron to Code for 50 Amino Acids
- Introduction: A cistron is a segment of DNA that codes for a single polypeptide chain. The number of nucleotides in a cistron depends on the number of amino acids in the polypeptide chain it codes for.
- Coding for Amino Acids: Amino acids are coded for by sets of three nucleotides called codons. There are 64 possible codons, but only 20 amino acids to code for. This means that some amino acids are coded for by more than one codon. For example, the amino acid leucine can be coded for by six different codons.
- Minimum Number of Nucleotides: In order to code for 50 amino acids, we need at least 150 nucleotides. This is because each amino acid is coded for by three nucleotides, so 50 amino acids will require 150 nucleotides.
- Stop Codons: In addition to codons that code for amino acids, there are three codons that act as stop signals, indicating the end of the polypeptide chain. These are known as stop codons, and they do not code for any amino acid. In order to ensure that the polypeptide chain is the correct length, we also need to include a stop codon at the end of the cistron. This means that we need at least 153 nucleotides to code for a polypeptide chain of 50 amino acids.
- Conclusion: The minimum number of nucleotides in a cistron to code for 50 amino acids is 153. This includes 150 nucleotides to code for the amino acids and 3 nucleotides to code for the stop codon at the end of the polypeptide chain.
Community Answer
To code 50 amino in a polypeptide chain what will be the minimum numbe...
Cistron is a double stranded DNA segment which codes polypeptides.
For coding 50 amino acids 51 codons are needed (50 codons + 1 stop codon)
Each codon is triplet. And triplet have 3 nitrogen bases.
So number of nucleotide for 51 codons =51*3=153
So total number of nucleotides will 153 *2 =306(Cistron is a double stranded DNA segment which codes polypeptides. So adding nucleotides of both the strands)
For coding 50 amino acids 51 codons are needed (50 codons + 1 stop codon)
Each codon is triplet. And triplet have 3 nitrogen bases.
So number of nucleotide for 51 codons =51*3=153
So total number of nucleotides will 153 *2 =306(Cistron is a double stranded DNA segment which codes polypeptides. So adding nucleotides of both the strands)
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To code 50 amino in a polypeptide chain what will be the minimum number. of nucleotide in cistron?
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