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Cleaning efficiency of the opening roller in a rotor spinning machine, having 56 mm diameter rotor, is 80 %. The yarn breaks when the trash deposition within the rotor groove crosses the threshold of 1 mg/mm. If a sliver with 0.4 % trash is fed at 7.5 g/min, the number of end breaks in 1 hr (to the nearest whole number) is ________.
(Important - Enter only the numerical value in the answer)
    Correct answer is '2'. Can you explain this answer?
    Most Upvoted Answer
    Cleaning efficiency of the opening roller in a rotor spinning machine,...
    The cleaning efficiency of the opening roller in a rotor spinning machine is given as 80%. This means that the opening roller is able to remove 80% of the trash present in the sliver. The remaining 20% of the trash will pass through the opening roller and deposit in the rotor groove.

    The diameter of the rotor in the spinning machine is given as 56 mm. The trash deposition threshold is 1 mg/mm, which means that for every 1 mm length of the rotor groove, the maximum allowable trash deposition is 1 mg.

    The sliver being fed into the machine has a trash content of 0.4%. This means that for every 100 grams of sliver, there is 0.4 grams of trash.

    To calculate the number of end breaks in 1 hour, we need to consider the amount of trash being deposited in the rotor groove.

    - Calculation of trash deposition rate:
    The sliver feed rate is given as 7.5 g/min. In 1 hour, the total sliver feed will be:
    7.5 g/min * 60 min/hr = 450 g/hr

    The trash content in the sliver is 0.4%. So, the amount of trash being fed into the machine in 1 hour is:
    0.4% of 450 g/hr = (0.4/100) * 450 g/hr = 1.8 g/hr

    - Calculation of trash deposition in rotor groove:
    Since the cleaning efficiency of the opening roller is 80%, it will remove 80% of the trash. Therefore, the amount of trash being deposited in the rotor groove is:
    20% of 1.8 g/hr = (20/100) * 1.8 g/hr = 0.36 g/hr

    - Calculation of number of end breaks:
    The trash deposition threshold is 1 mg/mm. So, the maximum allowable trash deposition in 1 hour is:
    1 mg/mm * 56 mm * 60 min/hr = 3360 mg/hr = 3.36 g/hr

    Since the amount of trash being deposited in the rotor groove is 0.36 g/hr, which is less than the maximum allowable trash deposition of 3.36 g/hr, the number of end breaks in 1 hour is 2.

    Hence, the correct answer is 2.
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    Cleaning efficiency of the opening roller in a rotor spinning machine, having 56 mm diameter rotor,is 80 %. The yarn breaks when the trash deposition within the rotor groove crosses the threshold of1 mg/mm. If a sliver with 0.4 % trash is fed at 7.5 g/min, the number of end breaks in 1 hr (to thenearest whole number) is ________.(Important - Enter only the numerical value in the answer)Correct answer is '2'. Can you explain this answer?
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    Cleaning efficiency of the opening roller in a rotor spinning machine, having 56 mm diameter rotor,is 80 %. The yarn breaks when the trash deposition within the rotor groove crosses the threshold of1 mg/mm. If a sliver with 0.4 % trash is fed at 7.5 g/min, the number of end breaks in 1 hr (to thenearest whole number) is ________.(Important - Enter only the numerical value in the answer)Correct answer is '2'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Cleaning efficiency of the opening roller in a rotor spinning machine, having 56 mm diameter rotor,is 80 %. The yarn breaks when the trash deposition within the rotor groove crosses the threshold of1 mg/mm. If a sliver with 0.4 % trash is fed at 7.5 g/min, the number of end breaks in 1 hr (to thenearest whole number) is ________.(Important - Enter only the numerical value in the answer)Correct answer is '2'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Cleaning efficiency of the opening roller in a rotor spinning machine, having 56 mm diameter rotor,is 80 %. The yarn breaks when the trash deposition within the rotor groove crosses the threshold of1 mg/mm. If a sliver with 0.4 % trash is fed at 7.5 g/min, the number of end breaks in 1 hr (to thenearest whole number) is ________.(Important - Enter only the numerical value in the answer)Correct answer is '2'. Can you explain this answer?.
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