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A 10 mm × 10 mm rod of a material is subjected to an axial pull of 4000 N. it was found that the lateral dimension of the rod changed to 9.9 mm × 9.9 mm. The Poisson’s ratio is (take modulus of rigidity of the material = 600 MPa)
  • a)
    1
  • b)
    0.01
  • c)
    0.43
  • d)
    0.23
Correct answer is option 'C'. Can you explain this answer?
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A 10 mm × 10 mm rod of a material is subjected to an axial pull ...
Given, A = 100 mm2, C =600 MPa
The axial stress induced in the rod,

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A 10 mm × 10 mm rod of a material is subjected to an axial pull ...
A 10 mm is a measurement of length. It is equivalent to 1 centimeter or 0.39 inches.
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A 10 mm × 10 mm rod of a material is subjected to an axial pull of 4000 N. it was found that the lateral dimension of the rod changed to 9.9 mm × 9.9 mm. The Poisson’s ratio is (take modulus of rigidity of the material = 600 MPa)a)1b)0.01c)0.43d)0.23Correct answer is option 'C'. Can you explain this answer?
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A 10 mm × 10 mm rod of a material is subjected to an axial pull of 4000 N. it was found that the lateral dimension of the rod changed to 9.9 mm × 9.9 mm. The Poisson’s ratio is (take modulus of rigidity of the material = 600 MPa)a)1b)0.01c)0.43d)0.23Correct answer is option 'C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A 10 mm × 10 mm rod of a material is subjected to an axial pull of 4000 N. it was found that the lateral dimension of the rod changed to 9.9 mm × 9.9 mm. The Poisson’s ratio is (take modulus of rigidity of the material = 600 MPa)a)1b)0.01c)0.43d)0.23Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 10 mm × 10 mm rod of a material is subjected to an axial pull of 4000 N. it was found that the lateral dimension of the rod changed to 9.9 mm × 9.9 mm. The Poisson’s ratio is (take modulus of rigidity of the material = 600 MPa)a)1b)0.01c)0.43d)0.23Correct answer is option 'C'. Can you explain this answer?.
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