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Let A be a collection of objects. An efficient method for converting it into a set is first to sort the objects of A. Then, walk through the sorted sequence and remove all duplicates. What is the running time of this method?
  • a)
    Ο(logn)
  • b)
    Ο(nlogn)
  • c)
    Ο(n)
  • d)
    Ο(n2)
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Let A be a collection of objects. An efficient method for converting i...
This takes O(nlogn) time to sort and n time to remove the duplicates. Overall, therefore, this is an O(nlogn) time method.
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Most Upvoted Answer
Let A be a collection of objects. An efficient method for converting i...
The running time of this method can be analyzed as follows:

1. Sorting the objects of A: The time complexity of sorting depends on the sorting algorithm used. Let's assume that the sorting algorithm used has a worst-case time complexity of O(n log n), where n is the number of objects in A.

2. Walking through the sorted sequence and removing duplicates: Since the sequence is sorted, we can easily identify and remove duplicates by comparing adjacent elements. This process will take O(n) time, as we need to iterate through each object once.

Therefore, the overall running time of this method is O(n log n) + O(n) = O(n log n), where n is the number of objects in A.
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Let A be a collection of objects. An efficient method for converting it into a set is first to sort the objects of A. Then, walk through the sorted sequence and remove all duplicates. What is the running time of this method?a)Ο(logn)b)Ο(nlogn)c)Ο(n)d)Ο(n2)Correct answer is option 'B'. Can you explain this answer?
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