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A system described by a linear, constant coefficient, ordinary, first order differential equation has an exact solution given by y(t) for t>0, when the forcing function is x(t) and the initial condition is y(0). If one wishes to modify the system so that the solution becomes -2y(t) for t>0, we need toa)change the initial condition to –y(0) and the forcing function to 2x(t)b)change the initial condition to 2y (0) and the forcing function to −x (t)c)change the initial condition to j √2y (0) and the forcing function to j √2x (t)d)change the initial condition to -2y(0) and the forcing function to −2x (t)Correct answer is option 'D'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A system described by a linear, constant coefficient, ordinary, first order differential equation has an exact solution given by y(t) for t>0, when the forcing function is x(t) and the initial condition is y(0). If one wishes to modify the system so that the solution becomes -2y(t) for t>0, we need toa)change the initial condition to –y(0) and the forcing function to 2x(t)b)change the initial condition to 2y (0) and the forcing function to −x (t)c)change the initial condition to j √2y (0) and the forcing function to j √2x (t)d)change the initial condition to -2y(0) and the forcing function to −2x (t)Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A system described by a linear, constant coefficient, ordinary, first order differential equation has an exact solution given by y(t) for t>0, when the forcing function is x(t) and the initial condition is y(0). If one wishes to modify the system so that the solution becomes -2y(t) for t>0, we need toa)change the initial condition to –y(0) and the forcing function to 2x(t)b)change the initial condition to 2y (0) and the forcing function to −x (t)c)change the initial condition to j √2y (0) and the forcing function to j √2x (t)d)change the initial condition to -2y(0) and the forcing function to −2x (t)Correct answer is option 'D'. Can you explain this answer?.

Solutions for A system described by a linear, constant coefficient, ordinary, first order differential equation has an exact solution given by y(t) for t>0, when the forcing function is x(t) and the initial condition is y(0). If one wishes to modify the system so that the solution becomes -2y(t) for t>0, we need toa)change the initial condition to –y(0) and the forcing function to 2x(t)b)change the initial condition to 2y (0) and the forcing function to −x (t)c)change the initial condition to j √2y (0) and the forcing function to j √2x (t)d)change the initial condition to -2y(0) and the forcing function to −2x (t)Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE. Download more important topics, notes, lectures and mock test series for GATE Exam by signing up for free.

Here you can find the meaning of A system described by a linear, constant coefficient, ordinary, first order differential equation has an exact solution given by y(t) for t>0, when the forcing function is x(t) and the initial condition is y(0). If one wishes to modify the system so that the solution becomes -2y(t) for t>0, we need toa)change the initial condition to –y(0) and the forcing function to 2x(t)b)change the initial condition to 2y (0) and the forcing function to −x (t)c)change the initial condition to j √2y (0) and the forcing function to j √2x (t)d)change the initial condition to -2y(0) and the forcing function to −2x (t)Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A system described by a linear, constant coefficient, ordinary, first order differential equation has an exact solution given by y(t) for t>0, when the forcing function is x(t) and the initial condition is y(0). If one wishes to modify the system so that the solution becomes -2y(t) for t>0, we need toa)change the initial condition to –y(0) and the forcing function to 2x(t)b)change the initial condition to 2y (0) and the forcing function to −x (t)c)change the initial condition to j √2y (0) and the forcing function to j √2x (t)d)change the initial condition to -2y(0) and the forcing function to −2x (t)Correct answer is option 'D'. Can you explain this answer?, a detailed solution for A system described by a linear, constant coefficient, ordinary, first order differential equation has an exact solution given by y(t) for t>0, when the forcing function is x(t) and the initial condition is y(0). If one wishes to modify the system so that the solution becomes -2y(t) for t>0, we need toa)change the initial condition to –y(0) and the forcing function to 2x(t)b)change the initial condition to 2y (0) and the forcing function to −x (t)c)change the initial condition to j √2y (0) and the forcing function to j √2x (t)d)change the initial condition to -2y(0) and the forcing function to −2x (t)Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of A system described by a linear, constant coefficient, ordinary, first order differential equation has an exact solution given by y(t) for t>0, when the forcing function is x(t) and the initial condition is y(0). If one wishes to modify the system so that the solution becomes -2y(t) for t>0, we need toa)change the initial condition to –y(0) and the forcing function to 2x(t)b)change the initial condition to 2y (0) and the forcing function to −x (t)c)change the initial condition to j √2y (0) and the forcing function to j √2x (t)d)change the initial condition to -2y(0) and the forcing function to −2x (t)Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A system described by a linear, constant coefficient, ordinary, first order differential equation has an exact solution given by y(t) for t>0, when the forcing function is x(t) and the initial condition is y(0). If one wishes to modify the system so that the solution becomes -2y(t) for t>0, we need toa)change the initial condition to –y(0) and the forcing function to 2x(t)b)change the initial condition to 2y (0) and the forcing function to −x (t)c)change the initial condition to j √2y (0) and the forcing function to j √2x (t)d)change the initial condition to -2y(0) and the forcing function to −2x (t)Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice GATE tests.