For the Ordinary Differential Equationwith initial conditionthe solution isa)andminus;10e2t + 10e3tb)5e2t +6e3tc)10e2t + 10e3td)andminus;5e2t + 6e3tCorrect answer is option 'A'. Can you explain this answer?

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For the Ordinary Differential Equation

with initial condition

the solution is

a)
−10e^2t + 10e^3t
b)
5e^2t +6e^3t
c)
10e^2t+ 10e^3t
d)
−5e^2t + 6e^3t

Correct answer is option 'A'. Can you explain this answer?

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For the Ordinary Differential Equationwith initial conditionthe soluti...

A.E. is m² – 5m + 6 = 0
⇒ m = 2, 3 so C_f = C₁e^2t + C₂e^3t.
PI = 0 and G. Solution is x = CF + PI =

Now, using initial conditions we get C₁ = –10, C₂ = 10.
x = –10e^2t + 10e^3t

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For the Ordinary Differential Equationwith initial conditionthe solution isa)−10e2t + 10e3tb)5e2t +6e3tc)10e2t + 10e3td)−5e2t + 6e3tCorrect answer is option 'A'. Can you explain this answer?

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