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H2O2 acts as both oxidising as well as reducing agent. As oxidising agent, its product is H2O but as reducingagent, its product is O2. Volume strength has great significance for chemical reactions. The strength of ‘10V’ means 1 volume (or litre) of H2O2 on decomposition (H2O2 → H2O + ½ O2) gives 10 volumes (or litre) of oxygen at NTP. 15 g Ba(MnO4)2 sample containing inert impurity is completely reacting with 100 mL of ‘11.2 V’ H2O2, then what will be the % purity of Ba (MnO4)2 in the sample : (Atomic mass : Ba = 137, Mn = 55)a)5%b)10%c)50%d)none of theseCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared
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the NEET exam syllabus. Information about H2O2 acts as both oxidising as well as reducing agent. As oxidising agent, its product is H2O but as reducingagent, its product is O2. Volume strength has great significance for chemical reactions. The strength of ‘10V’ means 1 volume (or litre) of H2O2 on decomposition (H2O2 → H2O + ½ O2) gives 10 volumes (or litre) of oxygen at NTP. 15 g Ba(MnO4)2 sample containing inert impurity is completely reacting with 100 mL of ‘11.2 V’ H2O2, then what will be the % purity of Ba (MnO4)2 in the sample : (Atomic mass : Ba = 137, Mn = 55)a)5%b)10%c)50%d)none of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for H2O2 acts as both oxidising as well as reducing agent. As oxidising agent, its product is H2O but as reducingagent, its product is O2. Volume strength has great significance for chemical reactions. The strength of ‘10V’ means 1 volume (or litre) of H2O2 on decomposition (H2O2 → H2O + ½ O2) gives 10 volumes (or litre) of oxygen at NTP. 15 g Ba(MnO4)2 sample containing inert impurity is completely reacting with 100 mL of ‘11.2 V’ H2O2, then what will be the % purity of Ba (MnO4)2 in the sample : (Atomic mass : Ba = 137, Mn = 55)a)5%b)10%c)50%d)none of theseCorrect answer is option 'C'. Can you explain this answer?.
Solutions for H2O2 acts as both oxidising as well as reducing agent. As oxidising agent, its product is H2O but as reducingagent, its product is O2. Volume strength has great significance for chemical reactions. The strength of ‘10V’ means 1 volume (or litre) of H2O2 on decomposition (H2O2 → H2O + ½ O2) gives 10 volumes (or litre) of oxygen at NTP. 15 g Ba(MnO4)2 sample containing inert impurity is completely reacting with 100 mL of ‘11.2 V’ H2O2, then what will be the % purity of Ba (MnO4)2 in the sample : (Atomic mass : Ba = 137, Mn = 55)a)5%b)10%c)50%d)none of theseCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
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Here you can find the meaning of H2O2 acts as both oxidising as well as reducing agent. As oxidising agent, its product is H2O but as reducingagent, its product is O2. Volume strength has great significance for chemical reactions. The strength of ‘10V’ means 1 volume (or litre) of H2O2 on decomposition (H2O2 → H2O + ½ O2) gives 10 volumes (or litre) of oxygen at NTP. 15 g Ba(MnO4)2 sample containing inert impurity is completely reacting with 100 mL of ‘11.2 V’ H2O2, then what will be the % purity of Ba (MnO4)2 in the sample : (Atomic mass : Ba = 137, Mn = 55)a)5%b)10%c)50%d)none of theseCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
H2O2 acts as both oxidising as well as reducing agent. As oxidising agent, its product is H2O but as reducingagent, its product is O2. Volume strength has great significance for chemical reactions. The strength of ‘10V’ means 1 volume (or litre) of H2O2 on decomposition (H2O2 → H2O + ½ O2) gives 10 volumes (or litre) of oxygen at NTP. 15 g Ba(MnO4)2 sample containing inert impurity is completely reacting with 100 mL of ‘11.2 V’ H2O2, then what will be the % purity of Ba (MnO4)2 in the sample : (Atomic mass : Ba = 137, Mn = 55)a)5%b)10%c)50%d)none of theseCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for H2O2 acts as both oxidising as well as reducing agent. As oxidising agent, its product is H2O but as reducingagent, its product is O2. Volume strength has great significance for chemical reactions. The strength of ‘10V’ means 1 volume (or litre) of H2O2 on decomposition (H2O2 → H2O + ½ O2) gives 10 volumes (or litre) of oxygen at NTP. 15 g Ba(MnO4)2 sample containing inert impurity is completely reacting with 100 mL of ‘11.2 V’ H2O2, then what will be the % purity of Ba (MnO4)2 in the sample : (Atomic mass : Ba = 137, Mn = 55)a)5%b)10%c)50%d)none of theseCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of H2O2 acts as both oxidising as well as reducing agent. As oxidising agent, its product is H2O but as reducingagent, its product is O2. Volume strength has great significance for chemical reactions. The strength of ‘10V’ means 1 volume (or litre) of H2O2 on decomposition (H2O2 → H2O + ½ O2) gives 10 volumes (or litre) of oxygen at NTP. 15 g Ba(MnO4)2 sample containing inert impurity is completely reacting with 100 mL of ‘11.2 V’ H2O2, then what will be the % purity of Ba (MnO4)2 in the sample : (Atomic mass : Ba = 137, Mn = 55)a)5%b)10%c)50%d)none of theseCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice H2O2 acts as both oxidising as well as reducing agent. As oxidising agent, its product is H2O but as reducingagent, its product is O2. Volume strength has great significance for chemical reactions. The strength of ‘10V’ means 1 volume (or litre) of H2O2 on decomposition (H2O2 → H2O + ½ O2) gives 10 volumes (or litre) of oxygen at NTP. 15 g Ba(MnO4)2 sample containing inert impurity is completely reacting with 100 mL of ‘11.2 V’ H2O2, then what will be the % purity of Ba (MnO4)2 in the sample : (Atomic mass : Ba = 137, Mn = 55)a)5%b)10%c)50%d)none of theseCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice NEET tests.