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For 8085 microprocessor, the following program is executed
MVI A, 05H;
MVIB, 05H;
PTR: ADD B;
DCR B;
JNZ PTR;
ADI 03H;
HLT;
At the end of program, accumulator contains
MVI A, 05H;
MVIB, 05H;
PTR: ADD B;
DCR B;
JNZ PTR;
ADI 03H;
HLT;
At the end of program, accumulator contains
- a)17 H
- b)20 H
- c)23 H
- d)05 H
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
For 8085 microprocessor, the following program is executedMVI A, 05H;M...
Accumulator changes as follows (05 + 05 + 04 +03 +02 +01)H
At the end of Loop accumulator contains = 14H
ADI O3H →A=(14+03)=17H
At the end of Loop accumulator contains = 14H
ADI O3H →A=(14+03)=17H
Most Upvoted Answer
For 8085 microprocessor, the following program is executedMVI A, 05H;M...
Explanation:
The program executes the following steps:
1. Load the accumulator with the value 05H
2. Load the register B with the value 05H
3. Add the value in register B to the accumulator
4. Decrement the value in register B
5. If the value in register B is not zero, jump to step 3
6. Add the value 03H to the accumulator
7. Halt the program
The program executes a loop where the value in register B is added to the accumulator and then decremented until the value in register B becomes zero.
After the loop, the value 03H is added to the accumulator, resulting in the value 08H in the accumulator.
Therefore, the correct answer is option 'A', which is 17H in hexadecimal.
The program executes the following steps:
1. Load the accumulator with the value 05H
2. Load the register B with the value 05H
3. Add the value in register B to the accumulator
4. Decrement the value in register B
5. If the value in register B is not zero, jump to step 3
6. Add the value 03H to the accumulator
7. Halt the program
The program executes a loop where the value in register B is added to the accumulator and then decremented until the value in register B becomes zero.
After the loop, the value 03H is added to the accumulator, resulting in the value 08H in the accumulator.
Therefore, the correct answer is option 'A', which is 17H in hexadecimal.
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For 8085 microprocessor, the following program is executedMVI A, 05H;MVIB, 05H;PTR: ADD B;DCR B;JNZ PTR;ADI 03H;HLT;At the end of program, accumulator containsa)17 Hb)20 Hc)23 Hd)05 HCorrect answer is option 'A'. Can you explain this answer?
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For 8085 microprocessor, the following program is executedMVI A, 05H;MVIB, 05H;PTR: ADD B;DCR B;JNZ PTR;ADI 03H;HLT;At the end of program, accumulator containsa)17 Hb)20 Hc)23 Hd)05 HCorrect answer is option 'A'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about For 8085 microprocessor, the following program is executedMVI A, 05H;MVIB, 05H;PTR: ADD B;DCR B;JNZ PTR;ADI 03H;HLT;At the end of program, accumulator containsa)17 Hb)20 Hc)23 Hd)05 HCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For 8085 microprocessor, the following program is executedMVI A, 05H;MVIB, 05H;PTR: ADD B;DCR B;JNZ PTR;ADI 03H;HLT;At the end of program, accumulator containsa)17 Hb)20 Hc)23 Hd)05 HCorrect answer is option 'A'. Can you explain this answer?.
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