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The following FIVE instructions were executed on an 8085 microprocessor.
MVI A, 33H
MVI B, 78H
ADD B
CMA
ANI 32H
The Accumulator value immediately after the execution of the fifth instruction is
MVI A, 33H
MVI B, 78H
ADD B
CMA
ANI 32H
The Accumulator value immediately after the execution of the fifth instruction is
- a)00H
- b)10H
- c)11H
- d)32H
Correct answer is option 'B'. Can you explain this answer?
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The following FIVE instructions were executed on an 8085 microprocesso...
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Explanation:
To determine the value of the accumulator after the execution of the fifth instruction, we need to analyze each instruction one by one.
Instruction 1: MVI A, 33H
- This instruction moves the immediate data 33H to the accumulator (register A).
- After this instruction, the accumulator contains the value 33H.
Instruction 2: MVI B, 78H
- This instruction moves the immediate data 78H to register B.
- After this instruction, register B contains the value 78H.
Instruction 3: ADD B
- This instruction adds the value in register B to the accumulator.
- The previous value in the accumulator (33H) is added to the value in register B (78H).
- The result of the addition is stored in the accumulator itself.
- The value in the accumulator is now 33H + 78H = ABH.
Instruction 4: DCR A
- This instruction decrements the value in the accumulator by 1.
- The previous value in the accumulator (ABH) is decremented by 1.
- The value in the accumulator is now AAH.
Instruction 5: ANI 32H
- This instruction performs a bitwise AND between the accumulator and the immediate data 32H.
- The previous value in the accumulator (AAH) is ANDed with 32H.
- The result of the bitwise AND is stored in the accumulator itself.
- The value in the accumulator is now AAH & 32H = 20H.
Therefore, the final value of the accumulator after the execution of the fifth instruction is 20H, which corresponds to option 'B'.
To determine the value of the accumulator after the execution of the fifth instruction, we need to analyze each instruction one by one.
Instruction 1: MVI A, 33H
- This instruction moves the immediate data 33H to the accumulator (register A).
- After this instruction, the accumulator contains the value 33H.
Instruction 2: MVI B, 78H
- This instruction moves the immediate data 78H to register B.
- After this instruction, register B contains the value 78H.
Instruction 3: ADD B
- This instruction adds the value in register B to the accumulator.
- The previous value in the accumulator (33H) is added to the value in register B (78H).
- The result of the addition is stored in the accumulator itself.
- The value in the accumulator is now 33H + 78H = ABH.
Instruction 4: DCR A
- This instruction decrements the value in the accumulator by 1.
- The previous value in the accumulator (ABH) is decremented by 1.
- The value in the accumulator is now AAH.
Instruction 5: ANI 32H
- This instruction performs a bitwise AND between the accumulator and the immediate data 32H.
- The previous value in the accumulator (AAH) is ANDed with 32H.
- The result of the bitwise AND is stored in the accumulator itself.
- The value in the accumulator is now AAH & 32H = 20H.
Therefore, the final value of the accumulator after the execution of the fifth instruction is 20H, which corresponds to option 'B'.
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The following FIVE instructions were executed on an 8085 microprocessor.MVI A, 33HMVI B, 78HADD BCMAANI 32HThe Accumulator value immediately after the execution of the fifth instruction isa)00Hb)10Hc)11Hd)32HCorrect answer is option 'B'. Can you explain this answer?
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