It takes 30 minutes to empty a half-full tank by draining it at a cons...
Vhalf= 30(s) drawing rate = s
Total volume =60 S tank
(s1 )(10)- (s)10= 30s
s1 (s) -s= 3s
s1= 4s
s1= 4drawing rate
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It takes 30 minutes to empty a half-full tank by draining it at a cons...
Understanding the problem:
Given that it takes 30 minutes to empty a half-full tank by draining it at a constant rate, we need to find the rate at which water has to be pumped in so that it gets fully filled in 10 minutes.
Approach:
Let's assume the draining rate is D and the filling rate is F. Since the tank is half-full and it takes 30 minutes to empty it, the draining rate is 1/30 of the tank capacity per minute. To fill the tank in 10 minutes, we need the total rate of pumping in to be 1/10 of the tank capacity per minute.
Solution:
- Draining rate (D) = 1/30 of tank capacity per minute
- Filling rate = 1/10 of tank capacity per minute
Now, to find the rate at which water has to be pumped in, we need to find the ratio of the filling rate to the draining rate:
Filling rate / Draining rate = (1/10) / (1/30) = 3
Therefore, the rate at which water has to be pumped in to fully fill the tank in 10 minutes is 3 times the draining rate, which corresponds to option 'A'.