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Reaction A → B is carried out in a reactor operating at steady state and 1 mol/s of pure A at 425°C enters the reactor. The outlet stream leaves the reactor at 325°C. The heat input to the reactor is 17kW. The heat of reaction at the reference temperature of 25°C is 30kJ/mol. The specific heat capacities (in kJ/mol.K) of A and B are 0.1 and 0.15, respectively.
The molar flowrate of B leaving the reactor, rounded to 2 decimal places, is ____mol/s.
Correct answer is '0.6'. Can you explain this answer?
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Reaction A → B is carried out in a reactor operating at steady s...
A → B
Suppose X be the conversion of reactant
Suppose X be the conversion of reactant
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Reaction A → B is carried out in a reactor operating at steady s...
Solution:
Given:
- Inlet molar flowrate of A = 1 mol/s
- Inlet temperature of A = 425°C
- Outlet temperature of A = 325°C
- Heat input to the reactor = 17 kW
- Heat of reaction at 25°C = 30 kJ/mol
- Specific heat capacity of A = 0.1 kJ/mol.K
- Specific heat capacity of B = 0.15 kJ/mol.K
To find:
Molar flowrate of B leaving the reactor
Step 1: Calculate the heat absorbed by A
The heat absorbed by A can be calculated using the formula:
Q = mcΔT
Where:
Q = Heat absorbed (kJ/s)
m = Molar flowrate of A (mol/s)
c = Specific heat capacity of A (kJ/mol.K)
ΔT = Change in temperature (K)
Using the given values:
Q = (1 mol/s)(0.1 kJ/mol.K)(325°C - 425°C)
Q = -10 kJ/s (negative sign indicates heat absorbed)
Step 2: Calculate the heat of reaction
The heat of reaction can be calculated using the formula:
ΔH = Q/n
Where:
ΔH = Heat of reaction at 25°C (kJ/mol)
Q = Heat input to the reactor (kJ/s)
n = Molar flowrate of A (mol/s)
Using the given values:
30 kJ/mol = (17 kW)/(1 mol/s)
Step 3: Calculate the molar flowrate of B
The molar flowrate of B can be calculated using the formula:
nB = (ΔH + Q)/ΔHr
Where:
nB = Molar flowrate of B (mol/s)
ΔH = Heat of reaction at 25°C (kJ/mol)
Q = Heat absorbed by A (kJ/s)
ΔHr = Heat of reaction (kJ/mol)
Using the calculated values:
nB = (30 kJ/mol - 10 kJ/s)/(30 kJ/mol)
nB = 0.6 mol/s
Therefore, the molar flowrate of B leaving the reactor is 0.6 mol/s.
Given:
- Inlet molar flowrate of A = 1 mol/s
- Inlet temperature of A = 425°C
- Outlet temperature of A = 325°C
- Heat input to the reactor = 17 kW
- Heat of reaction at 25°C = 30 kJ/mol
- Specific heat capacity of A = 0.1 kJ/mol.K
- Specific heat capacity of B = 0.15 kJ/mol.K
To find:
Molar flowrate of B leaving the reactor
Step 1: Calculate the heat absorbed by A
The heat absorbed by A can be calculated using the formula:
Q = mcΔT
Where:
Q = Heat absorbed (kJ/s)
m = Molar flowrate of A (mol/s)
c = Specific heat capacity of A (kJ/mol.K)
ΔT = Change in temperature (K)
Using the given values:
Q = (1 mol/s)(0.1 kJ/mol.K)(325°C - 425°C)
Q = -10 kJ/s (negative sign indicates heat absorbed)
Step 2: Calculate the heat of reaction
The heat of reaction can be calculated using the formula:
ΔH = Q/n
Where:
ΔH = Heat of reaction at 25°C (kJ/mol)
Q = Heat input to the reactor (kJ/s)
n = Molar flowrate of A (mol/s)
Using the given values:
30 kJ/mol = (17 kW)/(1 mol/s)
Step 3: Calculate the molar flowrate of B
The molar flowrate of B can be calculated using the formula:
nB = (ΔH + Q)/ΔHr
Where:
nB = Molar flowrate of B (mol/s)
ΔH = Heat of reaction at 25°C (kJ/mol)
Q = Heat absorbed by A (kJ/s)
ΔHr = Heat of reaction (kJ/mol)
Using the calculated values:
nB = (30 kJ/mol - 10 kJ/s)/(30 kJ/mol)
nB = 0.6 mol/s
Therefore, the molar flowrate of B leaving the reactor is 0.6 mol/s.
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Reaction A → B is carried out in a reactor operating at steady state and 1 mol/s of pure A at 425°C enters the reactor. The outlet stream leaves the reactor at 325°C. The heat input to the reactor is 17kW. The heat of reaction at the reference temperature of 25°C is 30kJ/mol. The specific heat capacities (in kJ/mol.K) of A and B are 0.1 and 0.15, respectively.The molar flowrate of B leaving the reactor, rounded to 2 decimal places, is ____mol/s.Correct answer is '0.6'. Can you explain this answer?
Question Description
Reaction A → B is carried out in a reactor operating at steady state and 1 mol/s of pure A at 425°C enters the reactor. The outlet stream leaves the reactor at 325°C. The heat input to the reactor is 17kW. The heat of reaction at the reference temperature of 25°C is 30kJ/mol. The specific heat capacities (in kJ/mol.K) of A and B are 0.1 and 0.15, respectively.The molar flowrate of B leaving the reactor, rounded to 2 decimal places, is ____mol/s.Correct answer is '0.6'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Reaction A → B is carried out in a reactor operating at steady state and 1 mol/s of pure A at 425°C enters the reactor. The outlet stream leaves the reactor at 325°C. The heat input to the reactor is 17kW. The heat of reaction at the reference temperature of 25°C is 30kJ/mol. The specific heat capacities (in kJ/mol.K) of A and B are 0.1 and 0.15, respectively.The molar flowrate of B leaving the reactor, rounded to 2 decimal places, is ____mol/s.Correct answer is '0.6'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Reaction A → B is carried out in a reactor operating at steady state and 1 mol/s of pure A at 425°C enters the reactor. The outlet stream leaves the reactor at 325°C. The heat input to the reactor is 17kW. The heat of reaction at the reference temperature of 25°C is 30kJ/mol. The specific heat capacities (in kJ/mol.K) of A and B are 0.1 and 0.15, respectively.The molar flowrate of B leaving the reactor, rounded to 2 decimal places, is ____mol/s.Correct answer is '0.6'. Can you explain this answer?.
Reaction A → B is carried out in a reactor operating at steady state and 1 mol/s of pure A at 425°C enters the reactor. The outlet stream leaves the reactor at 325°C. The heat input to the reactor is 17kW. The heat of reaction at the reference temperature of 25°C is 30kJ/mol. The specific heat capacities (in kJ/mol.K) of A and B are 0.1 and 0.15, respectively.The molar flowrate of B leaving the reactor, rounded to 2 decimal places, is ____mol/s.Correct answer is '0.6'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Reaction A → B is carried out in a reactor operating at steady state and 1 mol/s of pure A at 425°C enters the reactor. The outlet stream leaves the reactor at 325°C. The heat input to the reactor is 17kW. The heat of reaction at the reference temperature of 25°C is 30kJ/mol. The specific heat capacities (in kJ/mol.K) of A and B are 0.1 and 0.15, respectively.The molar flowrate of B leaving the reactor, rounded to 2 decimal places, is ____mol/s.Correct answer is '0.6'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Reaction A → B is carried out in a reactor operating at steady state and 1 mol/s of pure A at 425°C enters the reactor. The outlet stream leaves the reactor at 325°C. The heat input to the reactor is 17kW. The heat of reaction at the reference temperature of 25°C is 30kJ/mol. The specific heat capacities (in kJ/mol.K) of A and B are 0.1 and 0.15, respectively.The molar flowrate of B leaving the reactor, rounded to 2 decimal places, is ____mol/s.Correct answer is '0.6'. Can you explain this answer?.
Solutions for Reaction A → B is carried out in a reactor operating at steady state and 1 mol/s of pure A at 425°C enters the reactor. The outlet stream leaves the reactor at 325°C. The heat input to the reactor is 17kW. The heat of reaction at the reference temperature of 25°C is 30kJ/mol. The specific heat capacities (in kJ/mol.K) of A and B are 0.1 and 0.15, respectively.The molar flowrate of B leaving the reactor, rounded to 2 decimal places, is ____mol/s.Correct answer is '0.6'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
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