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An isothermal liquid phase zero order reaction A→B (k = 0.5 mol/m3-s) is carried out in a batch reactor. The initial concentration of A is 2 mol/m3. At 3 seconds from the start of the reaction, the concentration of A in mol/m3 is
 
Important : you should answer only the numeric value
    Correct answer is '0.5'. Can you explain this answer?
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    An isothermal liquid phase zero order reaction A→B (k = 0.5 mol/m...
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    An isothermal liquid phase zero order reaction A→B (k = 0.5 mol/m...
    → products takes place in a batch reactor. The initial concentration of A is 1 M and the reaction rate constant is 0.1 M/s. The reactor volume is 10 L. Determine the time required to reduce the concentration of A to 0.5 M.

    Solution:

    The rate law for a zero order reaction is given by:

    r = -k[A]^0 = -k

    Since the reaction is isothermal, the rate of the reaction is constant throughout the reaction time. Therefore, the integrated rate law for a zero order reaction is:

    [A]t = [A]0 - kt

    where [A]t is the concentration of A at time t, [A]0 is the initial concentration of A, k is the rate constant, and t is the reaction time.

    We need to find the time required to reduce the concentration of A to 0.5 M, which means that [A]t = 0.5 M.

    Substituting the given values, we get:

    0.5 = 1 - (0.1)t

    Solving for t, we get:

    t = (1 - 0.5) / 0.1 = 5 s

    Therefore, it will take 5 seconds to reduce the concentration of A to 0.5 M in the given batch reactor.
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    An isothermal liquid phase zero order reaction A→B (k = 0.5 mol/m3-s) is carried out in a batch reactor. The initial concentration of A is 2 mol/m3. At 3 seconds from the start of the reaction, the concentration of A in mol/m3 isImportant : you should answer only the numeric valueCorrect answer is '0.5'. Can you explain this answer?
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