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For two rolls of a fair die, the probability of getting a 4 in the first roll and a
number less than 4 in the second roll, up to 3 digits after the decimal point, is _______
number less than 4 in the second roll, up to 3 digits after the decimal point, is _______
Imp : you should answer only the numeric value
Correct answer is '0.0833'. Can you explain this answer?
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Verified Answer
For two rolls of a fair die, the probability of getting a 4 in the fir...
We known that, if two dice are thrown then total number of out comes
=62=39
Let E be the event of getting 4 in the first roll and a number less than 4 is the
second.
Then favorable cases to occur E are
=62=39
Let E be the event of getting 4 in the first roll and a number less than 4 is the
second.
Then favorable cases to occur E are
(4,1) (4,2), (4,3)
Re quired probability =3/36=1/12 =0.0833
Most Upvoted Answer
For two rolls of a fair die, the probability of getting a 4 in the fir...
The probability of getting a 4 in the first roll of a fair die can be calculated by dividing the number of favorable outcomes (1) by the total number of possible outcomes (6), which gives us 1/6.
Similarly, the probability of getting a number less than 4 in the second roll can be calculated by dividing the number of favorable outcomes (3) by the total number of possible outcomes (6), which gives us 3/6 or 1/2.
To find the probability of both events happening, we need to multiply the probabilities of each event occurring. So, the probability of getting a 4 in the first roll and a number less than 4 in the second roll is (1/6) * (1/2) = 1/12.
However, the question asks for the answer to be rounded to three decimal places. To do this, we divide 1 by 12 and round the result to three decimal places, which gives us 0.0833.
Therefore, the probability of getting a 4 in the first roll and a number less than 4 in the second roll is 0.0833, rounded to three decimal places.
Similarly, the probability of getting a number less than 4 in the second roll can be calculated by dividing the number of favorable outcomes (3) by the total number of possible outcomes (6), which gives us 3/6 or 1/2.
To find the probability of both events happening, we need to multiply the probabilities of each event occurring. So, the probability of getting a 4 in the first roll and a number less than 4 in the second roll is (1/6) * (1/2) = 1/12.
However, the question asks for the answer to be rounded to three decimal places. To do this, we divide 1 by 12 and round the result to three decimal places, which gives us 0.0833.
Therefore, the probability of getting a 4 in the first roll and a number less than 4 in the second roll is 0.0833, rounded to three decimal places.
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For two rolls of a fair die, the probability of getting a 4 in the first roll and anumber less than 4 in the second roll, up to 3 digits after the decimal point, is _______Imp : you should answer only the numeric valueCorrect answer is '0.0833'. Can you explain this answer?
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