Find the odd one in the following group: ALRVX, EPVZB, ITZDF, OYEIKa)ALRVXb)EPVZBc)ITZDFd)OYEIKCorrect answer is option 'D'. Can you explain this answer?

Question

Answer

Question Analysis:

The question presents a group of four words - ALRVX, EPVZB, ITZDF, OYEIK - and the task is to identify the odd one out. The words in the group seem to be random letter combinations, and there is no apparent pattern or theme.

Correct Answer Explanation:

The correct answer is option D, OYEIK. The reason is that all the other words in the group follow a similar pattern - they contain five letters, and the letters are arranged in alphabetical order. In contrast, OYEIK has five letters, but they are not in alphabetical order. The letters 'I' and 'K' are not in their correct alphabetical positions, which makes it the odd one out.

Summary:

• The task is to identify the odd one out from a group of four words - ALRVX, EPVZB, ITZDF, OYEIK.

• The correct answer is option D, OYEIK, because it does not follow the pattern of the other words in the group.

• All the other words contain five letters, and the letters are arranged in alphabetical order, whereas OYEIK has five letters, but they are not in alphabetical order.

Answer

Here in the first letter,
4 is added but in OYEIK the first letter has an addition of 6 (9 + 6 = 15).

Similarly, at the 2nd place, there is addition of 4 digits but at last there is addition of 5(20 + 5 = 25).

So, the last option is odd.

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