NEET Exam > NEET Questions > In Duma's method for estimation of Nitrogen,0...
Start Learning for Free
In Duma's method for estimation of Nitrogen,0.25g of an organic compound gave 40ml of Nitrogen collected at 300K temperature and 725mm pressure . If the aqueous tension at 300K is 25mm , the percentage of Nitrogen in the compound is
(A) 16.76
(B) 15.76
(C) 17.36
(D) 18.20
The correct answer is (A) , can anyone explain it?
(A) 16.76
(B) 15.76
(C) 17.36
(D) 18.20
The correct answer is (A) , can anyone explain it?
Most Upvoted Answer
In Duma's method for estimation of Nitrogen,0.25g of an organic compou...
Community Answer
In Duma's method for estimation of Nitrogen,0.25g of an organic compou...
Duma's Method for Estimation of Nitrogen
Duma's method is a common method used to estimate the percentage of nitrogen in an organic compound. It involves the combustion of the compound in an atmosphere of pure oxygen, which converts all the nitrogen in the compound into nitric oxide (NO). The generated nitric oxide is then collected and measured.
Given Data
- Mass of organic compound = 0.25g
- Volume of nitrogen collected = 40ml
- Temperature = 300K
- Pressure = 725mm
- Aqueous tension at 300K = 25mm
Calculating Moles of Nitrogen
To calculate the moles of nitrogen, we can use the ideal gas law equation:
PV = nRT
Where:
- P is the pressure
- V is the volume
- n is the number of moles
- R is the ideal gas constant
- T is the temperature in Kelvin
Given:
- P = 725mm - 25mm (subtracting aqueous tension)
- V = 40ml = 0.04L
- T = 300K
Converting pressure to atm:
1 atm = 760mm
725mm = (725/760) atm ≈ 0.954 atm
Plugging in the values:
0.954 atm * 0.04 L = n * 0.0821 atm L/mol K * 300K
Simplifying the equation:
0.03816 = 0.0821n
Solving for n:
n ≈ 0.03816 / 0.0821
n ≈ 0.465 mol
Calculating the Percentage of Nitrogen
To calculate the percentage of nitrogen in the compound, we need to know the molar mass of the compound.
Assuming the molar mass of the organic compound is M grams/mol, then:
0.25g of the organic compound contains 0.25/M moles of the compound.
Since 0.465 moles of nitrogen are obtained from 0.25g of the organic compound, we can equate the two values:
0.25/M = 0.465
Solving for M:
M = 0.25 / 0.465
M ≈ 0.5376 g/mol
The molar mass of nitrogen is approximately 14 g/mol. Therefore, the percentage of nitrogen in the compound is:
(14 / 0.5376) * 100 ≈ 26.02%
However, the correct answer given is 16.76%. It seems there may be an error in the provided data or calculations. Please double-check the values and calculations to ensure accuracy.
Duma's method is a common method used to estimate the percentage of nitrogen in an organic compound. It involves the combustion of the compound in an atmosphere of pure oxygen, which converts all the nitrogen in the compound into nitric oxide (NO). The generated nitric oxide is then collected and measured.
Given Data
- Mass of organic compound = 0.25g
- Volume of nitrogen collected = 40ml
- Temperature = 300K
- Pressure = 725mm
- Aqueous tension at 300K = 25mm
Calculating Moles of Nitrogen
To calculate the moles of nitrogen, we can use the ideal gas law equation:
PV = nRT
Where:
- P is the pressure
- V is the volume
- n is the number of moles
- R is the ideal gas constant
- T is the temperature in Kelvin
Given:
- P = 725mm - 25mm (subtracting aqueous tension)
- V = 40ml = 0.04L
- T = 300K
Converting pressure to atm:
1 atm = 760mm
725mm = (725/760) atm ≈ 0.954 atm
Plugging in the values:
0.954 atm * 0.04 L = n * 0.0821 atm L/mol K * 300K
Simplifying the equation:
0.03816 = 0.0821n
Solving for n:
n ≈ 0.03816 / 0.0821
n ≈ 0.465 mol
Calculating the Percentage of Nitrogen
To calculate the percentage of nitrogen in the compound, we need to know the molar mass of the compound.
Assuming the molar mass of the organic compound is M grams/mol, then:
0.25g of the organic compound contains 0.25/M moles of the compound.
Since 0.465 moles of nitrogen are obtained from 0.25g of the organic compound, we can equate the two values:
0.25/M = 0.465
Solving for M:
M = 0.25 / 0.465
M ≈ 0.5376 g/mol
The molar mass of nitrogen is approximately 14 g/mol. Therefore, the percentage of nitrogen in the compound is:
(14 / 0.5376) * 100 ≈ 26.02%
However, the correct answer given is 16.76%. It seems there may be an error in the provided data or calculations. Please double-check the values and calculations to ensure accuracy.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
In Duma's method for estimation of Nitrogen,0.25g of an organic compound gave 40ml of Nitrogen collected at 300K temperature and 725mm pressure . If the aqueous tension at 300K is 25mm , the percentage of Nitrogen in the compound is (A) 16.76 (B) 15.76 (C) 17.36 (D) 18.20The correct answer is (A) , can anyone explain it?
Question Description
In Duma's method for estimation of Nitrogen,0.25g of an organic compound gave 40ml of Nitrogen collected at 300K temperature and 725mm pressure . If the aqueous tension at 300K is 25mm , the percentage of Nitrogen in the compound is (A) 16.76 (B) 15.76 (C) 17.36 (D) 18.20The correct answer is (A) , can anyone explain it? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In Duma's method for estimation of Nitrogen,0.25g of an organic compound gave 40ml of Nitrogen collected at 300K temperature and 725mm pressure . If the aqueous tension at 300K is 25mm , the percentage of Nitrogen in the compound is (A) 16.76 (B) 15.76 (C) 17.36 (D) 18.20The correct answer is (A) , can anyone explain it? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In Duma's method for estimation of Nitrogen,0.25g of an organic compound gave 40ml of Nitrogen collected at 300K temperature and 725mm pressure . If the aqueous tension at 300K is 25mm , the percentage of Nitrogen in the compound is (A) 16.76 (B) 15.76 (C) 17.36 (D) 18.20The correct answer is (A) , can anyone explain it?.
In Duma's method for estimation of Nitrogen,0.25g of an organic compound gave 40ml of Nitrogen collected at 300K temperature and 725mm pressure . If the aqueous tension at 300K is 25mm , the percentage of Nitrogen in the compound is (A) 16.76 (B) 15.76 (C) 17.36 (D) 18.20The correct answer is (A) , can anyone explain it? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In Duma's method for estimation of Nitrogen,0.25g of an organic compound gave 40ml of Nitrogen collected at 300K temperature and 725mm pressure . If the aqueous tension at 300K is 25mm , the percentage of Nitrogen in the compound is (A) 16.76 (B) 15.76 (C) 17.36 (D) 18.20The correct answer is (A) , can anyone explain it? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In Duma's method for estimation of Nitrogen,0.25g of an organic compound gave 40ml of Nitrogen collected at 300K temperature and 725mm pressure . If the aqueous tension at 300K is 25mm , the percentage of Nitrogen in the compound is (A) 16.76 (B) 15.76 (C) 17.36 (D) 18.20The correct answer is (A) , can anyone explain it?.
Solutions for In Duma's method for estimation of Nitrogen,0.25g of an organic compound gave 40ml of Nitrogen collected at 300K temperature and 725mm pressure . If the aqueous tension at 300K is 25mm , the percentage of Nitrogen in the compound is (A) 16.76 (B) 15.76 (C) 17.36 (D) 18.20The correct answer is (A) , can anyone explain it? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of In Duma's method for estimation of Nitrogen,0.25g of an organic compound gave 40ml of Nitrogen collected at 300K temperature and 725mm pressure . If the aqueous tension at 300K is 25mm , the percentage of Nitrogen in the compound is (A) 16.76 (B) 15.76 (C) 17.36 (D) 18.20The correct answer is (A) , can anyone explain it? defined & explained in the simplest way possible. Besides giving the explanation of
In Duma's method for estimation of Nitrogen,0.25g of an organic compound gave 40ml of Nitrogen collected at 300K temperature and 725mm pressure . If the aqueous tension at 300K is 25mm , the percentage of Nitrogen in the compound is (A) 16.76 (B) 15.76 (C) 17.36 (D) 18.20The correct answer is (A) , can anyone explain it?, a detailed solution for In Duma's method for estimation of Nitrogen,0.25g of an organic compound gave 40ml of Nitrogen collected at 300K temperature and 725mm pressure . If the aqueous tension at 300K is 25mm , the percentage of Nitrogen in the compound is (A) 16.76 (B) 15.76 (C) 17.36 (D) 18.20The correct answer is (A) , can anyone explain it? has been provided alongside types of In Duma's method for estimation of Nitrogen,0.25g of an organic compound gave 40ml of Nitrogen collected at 300K temperature and 725mm pressure . If the aqueous tension at 300K is 25mm , the percentage of Nitrogen in the compound is (A) 16.76 (B) 15.76 (C) 17.36 (D) 18.20The correct answer is (A) , can anyone explain it? theory, EduRev gives you an
ample number of questions to practice In Duma's method for estimation of Nitrogen,0.25g of an organic compound gave 40ml of Nitrogen collected at 300K temperature and 725mm pressure . If the aqueous tension at 300K is 25mm , the percentage of Nitrogen in the compound is (A) 16.76 (B) 15.76 (C) 17.36 (D) 18.20The correct answer is (A) , can anyone explain it? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup