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A source of sound of frequency 256 Hz is moving rapidly towards a wall with a velocity of 5m/s. How many beats per sec, will be heard if sound travels at a speed of 330 m/s, and observer is between the source and the wall?
Correct answer is '0'. Can you explain this answer?
Verified Answer
A source of sound of frequency 256 Hz is moving rapidly towards a wall...
In this situation, the source is moving towards the observer. Hence he will hear the sound of frequency n’ as given by
= 259.9 Hz
The same frequency is received by the wall. This frequency is reflected back towards observer. The wall with act as a source of frequency n’. Now source and observer both are at rest. The apparent frequency received by observer
n” = n’ = 259.9 Hz
∴ Beat frequency = n” - n’ = n’ ~ n’ = 0
= 259.9 Hz
The same frequency is received by the wall. This frequency is reflected back towards observer. The wall with act as a source of frequency n’. Now source and observer both are at rest. The apparent frequency received by observer
n” = n’ = 259.9 Hz
∴ Beat frequency = n” - n’ = n’ ~ n’ = 0
Most Upvoted Answer
A source of sound of frequency 256 Hz is moving rapidly towards a wall...
Explanation:
What are Beats?
Beats refer to the phenomenon of interference of two waves of slightly different frequencies, resulting in the periodic variation of amplitude of the resultant wave.
Formula for Beats:
The frequency of the beats heard (fbeat) is given by the difference between the frequency of two waves (f1 and f2) divided by the speed of sound (v).
fbeat = |f1 - f2| / v
Given:
- Frequency of sound source (f1) = 256 Hz
- Velocity of sound (v) = 330 m/s
- Velocity of sound source (vs) = 5 m/s (towards the wall)
- Observer is between the source and wall.
Approach:
When the sound source moves towards the observer, the frequency of the sound wave received by the observer increases due to the Doppler effect.
The apparent frequency of the sound wave received by the observer (f1') is given by:
f1' = f1 (v + vs) / (v + vo)
where vo is the velocity of the observer.
In this case, the observer is between the source and the wall, so the velocity of the observer (vo) is negative.
f1' = 256 (330 + 5) / (330 - vo)
To hear beats, there must be two sound sources with slightly different frequencies. In this case, there is only one sound source (the moving source). Therefore, there can be no beats.
Answer:
0 beats per second will be heard.
What are Beats?
Beats refer to the phenomenon of interference of two waves of slightly different frequencies, resulting in the periodic variation of amplitude of the resultant wave.
Formula for Beats:
The frequency of the beats heard (fbeat) is given by the difference between the frequency of two waves (f1 and f2) divided by the speed of sound (v).
fbeat = |f1 - f2| / v
Given:
- Frequency of sound source (f1) = 256 Hz
- Velocity of sound (v) = 330 m/s
- Velocity of sound source (vs) = 5 m/s (towards the wall)
- Observer is between the source and wall.
Approach:
When the sound source moves towards the observer, the frequency of the sound wave received by the observer increases due to the Doppler effect.
The apparent frequency of the sound wave received by the observer (f1') is given by:
f1' = f1 (v + vs) / (v + vo)
where vo is the velocity of the observer.
In this case, the observer is between the source and the wall, so the velocity of the observer (vo) is negative.
f1' = 256 (330 + 5) / (330 - vo)
To hear beats, there must be two sound sources with slightly different frequencies. In this case, there is only one sound source (the moving source). Therefore, there can be no beats.
Answer:
0 beats per second will be heard.
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A source of sound of frequency 256 Hz is moving rapidly towards a wall with a velocity of 5m/s. How many beats per sec, will be heard if sound travels at a speed of 330 m/s, and observer is between the source and the wall?Correct answer is '0'. Can you explain this answer?
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A source of sound of frequency 256 Hz is moving rapidly towards a wall with a velocity of 5m/s. How many beats per sec, will be heard if sound travels at a speed of 330 m/s, and observer is between the source and the wall?Correct answer is '0'. Can you explain this answer? for GATE 2025 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A source of sound of frequency 256 Hz is moving rapidly towards a wall with a velocity of 5m/s. How many beats per sec, will be heard if sound travels at a speed of 330 m/s, and observer is between the source and the wall?Correct answer is '0'. Can you explain this answer? covers all topics & solutions for GATE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A source of sound of frequency 256 Hz is moving rapidly towards a wall with a velocity of 5m/s. How many beats per sec, will be heard if sound travels at a speed of 330 m/s, and observer is between the source and the wall?Correct answer is '0'. Can you explain this answer?.
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