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At normal temperature (0°C) and normal pressure (1.013 x105N/m2) when 1 gm. of water freezes, its volume increases by 0.091 cm3. What is the change in internal energy.a)ΔU = — 366 Jouleb)ΔU = — 336 Joulec)ΔU = 400 Jouled)ΔU = -400 JouleCorrect answer is option 'B'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about At normal temperature (0°C) and normal pressure (1.013 x105N/m2) when 1 gm. of water freezes, its volume increases by 0.091 cm3. What is the change in internal energy.a)ΔU = — 366 Jouleb)ΔU = — 336 Joulec)ΔU = 400 Jouled)ΔU = -400 JouleCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for At normal temperature (0°C) and normal pressure (1.013 x105N/m2) when 1 gm. of water freezes, its volume increases by 0.091 cm3. What is the change in internal energy.a)ΔU = — 366 Jouleb)ΔU = — 336 Joulec)ΔU = 400 Jouled)ΔU = -400 JouleCorrect answer is option 'B'. Can you explain this answer?.

Solutions for At normal temperature (0°C) and normal pressure (1.013 x105N/m2) when 1 gm. of water freezes, its volume increases by 0.091 cm3. What is the change in internal energy.a)ΔU = — 366 Jouleb)ΔU = — 336 Joulec)ΔU = 400 Jouled)ΔU = -400 JouleCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE. Download more important topics, notes, lectures and mock test series for GATE Exam by signing up for free.

Here you can find the meaning of At normal temperature (0°C) and normal pressure (1.013 x105N/m2) when 1 gm. of water freezes, its volume increases by 0.091 cm3. What is the change in internal energy.a)ΔU = — 366 Jouleb)ΔU = — 336 Joulec)ΔU = 400 Jouled)ΔU = -400 JouleCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of At normal temperature (0°C) and normal pressure (1.013 x105N/m2) when 1 gm. of water freezes, its volume increases by 0.091 cm3. What is the change in internal energy.a)ΔU = — 366 Jouleb)ΔU = — 336 Joulec)ΔU = 400 Jouled)ΔU = -400 JouleCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for At normal temperature (0°C) and normal pressure (1.013 x105N/m2) when 1 gm. of water freezes, its volume increases by 0.091 cm3. What is the change in internal energy.a)ΔU = — 366 Jouleb)ΔU = — 336 Joulec)ΔU = 400 Jouled)ΔU = -400 JouleCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of At normal temperature (0°C) and normal pressure (1.013 x105N/m2) when 1 gm. of water freezes, its volume increases by 0.091 cm3. What is the change in internal energy.a)ΔU = — 366 Jouleb)ΔU = — 336 Joulec)ΔU = 400 Jouled)ΔU = -400 JouleCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice At normal temperature (0°C) and normal pressure (1.013 x105N/m2) when 1 gm. of water freezes, its volume increases by 0.091 cm3. What is the change in internal energy.a)ΔU = — 366 Jouleb)ΔU = — 336 Joulec)ΔU = 400 Jouled)ΔU = -400 JouleCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice GATE tests.