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A quantity of air (y = 1.4) at 27°C is suddenly compressed to one third of its volume. Calculate the change in temperature in °C.
Correct answer is '165'. Can you explain this answer?
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A quantity of air (y = 1.4) at 27°C is suddenly compressed to one ...
When the air is compressed slowly, the heat generated conducts away to the surroundings. Thus it is an isothermal process, temperatures remains constant throughout, i.e., there is no change in temperature.
When the air is compressed suddenly, the process is adiabatic.
Hence
If T1, V1 be the initial and T2, V2 the final temperature and volume respectively, then
or
Thus
or T2 = 300 (3)04 = 465.5 K = (465.5 - 273) = 192.5°C
∴ Change in temperature T2 - T1 = 192°C - 27°C = 165°C.
When the air is compressed suddenly, the process is adiabatic.
Hence
If T1, V1 be the initial and T2, V2 the final temperature and volume respectively, then
or
Thus
or T2 = 300 (3)04 = 465.5 K = (465.5 - 273) = 192.5°C
∴ Change in temperature T2 - T1 = 192°C - 27°C = 165°C.
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A quantity of air (y = 1.4) at 27°C is suddenly compressed to one third of its volume. Calculate the change in temperature in °C.Correct answer is '165'. Can you explain this answer?
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