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A Carnot engine operating between two temperatures 727°c and 27°c is supplied heat energy at the rate of 500 Joule / cycle. Sixty percent of the work output is used to drive a refrigerator, which reject heat to the surrounding at 27°c. If the refrigerator removes 1050 Joule of heat per cycle from the low temperature reservoir. Thena)Work input = 210 Jb)Work input = 270 Jc)Temperature of reservoir = 250 kd)Temperature of reservoir = 230 kCorrect answer is option 'A,C'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A Carnot engine operating between two temperatures 727°c and 27°c is supplied heat energy at the rate of 500 Joule / cycle. Sixty percent of the work output is used to drive a refrigerator, which reject heat to the surrounding at 27°c. If the refrigerator removes 1050 Joule of heat per cycle from the low temperature reservoir. Thena)Work input = 210 Jb)Work input = 270 Jc)Temperature of reservoir = 250 kd)Temperature of reservoir = 230 kCorrect answer is option 'A,C'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A Carnot engine operating between two temperatures 727°c and 27°c is supplied heat energy at the rate of 500 Joule / cycle. Sixty percent of the work output is used to drive a refrigerator, which reject heat to the surrounding at 27°c. If the refrigerator removes 1050 Joule of heat per cycle from the low temperature reservoir. Thena)Work input = 210 Jb)Work input = 270 Jc)Temperature of reservoir = 250 kd)Temperature of reservoir = 230 kCorrect answer is option 'A,C'. Can you explain this answer?.

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Here you can find the meaning of A Carnot engine operating between two temperatures 727°c and 27°c is supplied heat energy at the rate of 500 Joule / cycle. Sixty percent of the work output is used to drive a refrigerator, which reject heat to the surrounding at 27°c. If the refrigerator removes 1050 Joule of heat per cycle from the low temperature reservoir. Thena)Work input = 210 Jb)Work input = 270 Jc)Temperature of reservoir = 250 kd)Temperature of reservoir = 230 kCorrect answer is option 'A,C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A Carnot engine operating between two temperatures 727°c and 27°c is supplied heat energy at the rate of 500 Joule / cycle. Sixty percent of the work output is used to drive a refrigerator, which reject heat to the surrounding at 27°c. If the refrigerator removes 1050 Joule of heat per cycle from the low temperature reservoir. Thena)Work input = 210 Jb)Work input = 270 Jc)Temperature of reservoir = 250 kd)Temperature of reservoir = 230 kCorrect answer is option 'A,C'. Can you explain this answer?, a detailed solution for A Carnot engine operating between two temperatures 727°c and 27°c is supplied heat energy at the rate of 500 Joule / cycle. Sixty percent of the work output is used to drive a refrigerator, which reject heat to the surrounding at 27°c. If the refrigerator removes 1050 Joule of heat per cycle from the low temperature reservoir. Thena)Work input = 210 Jb)Work input = 270 Jc)Temperature of reservoir = 250 kd)Temperature of reservoir = 230 kCorrect answer is option 'A,C'. Can you explain this answer? has been provided alongside types of A Carnot engine operating between two temperatures 727°c and 27°c is supplied heat energy at the rate of 500 Joule / cycle. Sixty percent of the work output is used to drive a refrigerator, which reject heat to the surrounding at 27°c. If the refrigerator removes 1050 Joule of heat per cycle from the low temperature reservoir. Thena)Work input = 210 Jb)Work input = 270 Jc)Temperature of reservoir = 250 kd)Temperature of reservoir = 230 kCorrect answer is option 'A,C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A Carnot engine operating between two temperatures 727°c and 27°c is supplied heat energy at the rate of 500 Joule / cycle. Sixty percent of the work output is used to drive a refrigerator, which reject heat to the surrounding at 27°c. If the refrigerator removes 1050 Joule of heat per cycle from the low temperature reservoir. Thena)Work input = 210 Jb)Work input = 270 Jc)Temperature of reservoir = 250 kd)Temperature of reservoir = 230 kCorrect answer is option 'A,C'. Can you explain this answer? tests, examples and also practice GATE tests.