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If N to the base A is Avogadro number, then how many electrons are present in 4.2 g of n^-3?
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Calculating the number of electrons in n^-3
- First, we need to find the molar mass of n^-3:
- The molar mass of nitrogen (N) is approximately 14 g/mol.
- Since n^-3 has a charge of -3, we add 3 to the molar mass of nitrogen to get the molar mass of n^-3, which is 17 g/mol.
- Next, we calculate the number of moles of n^-3 in 4.2 g:
- Number of moles = mass / molar mass
- Number of moles = 4.2 g / 17 g/mol
- Number of moles ≈ 0.247 moles
- Now, we use Avogadro's number to find the number of n^-3 molecules:
- Avogadro's number is the number of entities (atoms, molecules, ions, etc.) in one mole of a substance, which is approximately 6.022 x 10^23.
- Number of n^-3 molecules = number of moles x Avogadro's number
- Number of n^-3 molecules ≈ 0.247 moles x 6.022 x 10^23 molecules/mol
- Finally, since n^-3 has 3 electrons, we multiply the number of n^-3 molecules by 3 to find the total number of electrons:
- Number of electrons = number of n^-3 molecules x 3
- Number of electrons ≈ 0.247 moles x 6.022 x 10^23 molecules/mol x 3
Therefore, there are approximately 3.36 x 10^23 electrons present in 4.2 g of n^-3.
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If N to the base A is Avogadro number, then how many electrons are present in 4.2 g of n^-3?
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