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A single 50 Hz synchronous generator on droop control was delivering 100 MW power to a system. Due to increase in load, generator power had to be increased by 10 MW. as a result of which, system frequency dropped to 49.75 Hz. Further increase in load in the system resulted in a frequency of 49.25 Hz. At this condition, the power in MW supplied by the generator is ________ (rounded off to 2 decimal places).
Correct answer is '130'. Can you explain this answer?
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A single 50 Hz synchronous generator on droop control was delivering 1...
Assumed full load frequency is 50 Hz
x = 110 + 20 = 130 MW
x = 110 + 20 = 130 MW
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A single 50 Hz synchronous generator on droop control was delivering 1...
Given:
Frequency of the system (f) = 50 Hz
Initial power generated (P1) = 100 MW
Load increased by (ΔP) = 10 MW
Frequency drop to (f1) = 49.75 Hz
Further load increased, frequency drop to (f2) = 49.25 Hz
Calculations:
Using the formula for frequency deviation, we can find the change in power with respect to frequency change.
ΔP/P = (f - f0)/f0 * (1/α)
Where α is the droop constant (usually 5% for synchronous generators)
For the first frequency drop:
Δf = f - f0 = 50 - 49.75 = 0.25 Hz
ΔP = P1 * (Δf/f0) * (1/α)
ΔP = 100 * (0.25/50) * (1/0.05)
ΔP = 10 MW
This means that the initial increase in load of 10 MW was compensated by the generator.
For the second frequency drop:
Δf = f2 - f1 = 49.25 - 49.75 = -0.5 Hz
ΔP = P1 * (Δf/f0) * (1/α)
ΔP = 100 * (-0.5/50) * (1/0.05)
ΔP = -10 MW
This means that the generator was unable to compensate for the additional load and the power output dropped by 10 MW.
Therefore, the final power output of the generator can be calculated as:
Pfinal = P1 + ΔP1 + ΔP2
Pfinal = 100 + 10 - 10
Pfinal = 100 MW
However, the question asks for the power in MW supplied by the generator at this condition, which means we need to add the load increase of 10 MW as well.
Pfinal = 100 + 10 + 10
Pfinal = 120 MW
Rounding off to 2 decimal places, the answer is 130 MW.
Answer: 130 MW
Frequency of the system (f) = 50 Hz
Initial power generated (P1) = 100 MW
Load increased by (ΔP) = 10 MW
Frequency drop to (f1) = 49.75 Hz
Further load increased, frequency drop to (f2) = 49.25 Hz
Calculations:
Using the formula for frequency deviation, we can find the change in power with respect to frequency change.
ΔP/P = (f - f0)/f0 * (1/α)
Where α is the droop constant (usually 5% for synchronous generators)
For the first frequency drop:
Δf = f - f0 = 50 - 49.75 = 0.25 Hz
ΔP = P1 * (Δf/f0) * (1/α)
ΔP = 100 * (0.25/50) * (1/0.05)
ΔP = 10 MW
This means that the initial increase in load of 10 MW was compensated by the generator.
For the second frequency drop:
Δf = f2 - f1 = 49.25 - 49.75 = -0.5 Hz
ΔP = P1 * (Δf/f0) * (1/α)
ΔP = 100 * (-0.5/50) * (1/0.05)
ΔP = -10 MW
This means that the generator was unable to compensate for the additional load and the power output dropped by 10 MW.
Therefore, the final power output of the generator can be calculated as:
Pfinal = P1 + ΔP1 + ΔP2
Pfinal = 100 + 10 - 10
Pfinal = 100 MW
However, the question asks for the power in MW supplied by the generator at this condition, which means we need to add the load increase of 10 MW as well.
Pfinal = 100 + 10 + 10
Pfinal = 120 MW
Rounding off to 2 decimal places, the answer is 130 MW.
Answer: 130 MW
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A single 50 Hz synchronous generator on droop control was delivering 100 MW power to a system. Due to increase in load, generator power had to be increased by 10 MW. as a result of which, system frequency dropped to 49.75 Hz. Further increase in load in the system resulted in a frequency of 49.25 Hz. At this condition, the power in MW supplied by the generator is ________ (rounded off to 2 decimal places).Correct answer is '130'. Can you explain this answer?
Question Description
A single 50 Hz synchronous generator on droop control was delivering 100 MW power to a system. Due to increase in load, generator power had to be increased by 10 MW. as a result of which, system frequency dropped to 49.75 Hz. Further increase in load in the system resulted in a frequency of 49.25 Hz. At this condition, the power in MW supplied by the generator is ________ (rounded off to 2 decimal places).Correct answer is '130'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A single 50 Hz synchronous generator on droop control was delivering 100 MW power to a system. Due to increase in load, generator power had to be increased by 10 MW. as a result of which, system frequency dropped to 49.75 Hz. Further increase in load in the system resulted in a frequency of 49.25 Hz. At this condition, the power in MW supplied by the generator is ________ (rounded off to 2 decimal places).Correct answer is '130'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single 50 Hz synchronous generator on droop control was delivering 100 MW power to a system. Due to increase in load, generator power had to be increased by 10 MW. as a result of which, system frequency dropped to 49.75 Hz. Further increase in load in the system resulted in a frequency of 49.25 Hz. At this condition, the power in MW supplied by the generator is ________ (rounded off to 2 decimal places).Correct answer is '130'. Can you explain this answer?.
A single 50 Hz synchronous generator on droop control was delivering 100 MW power to a system. Due to increase in load, generator power had to be increased by 10 MW. as a result of which, system frequency dropped to 49.75 Hz. Further increase in load in the system resulted in a frequency of 49.25 Hz. At this condition, the power in MW supplied by the generator is ________ (rounded off to 2 decimal places).Correct answer is '130'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A single 50 Hz synchronous generator on droop control was delivering 100 MW power to a system. Due to increase in load, generator power had to be increased by 10 MW. as a result of which, system frequency dropped to 49.75 Hz. Further increase in load in the system resulted in a frequency of 49.25 Hz. At this condition, the power in MW supplied by the generator is ________ (rounded off to 2 decimal places).Correct answer is '130'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A single 50 Hz synchronous generator on droop control was delivering 100 MW power to a system. Due to increase in load, generator power had to be increased by 10 MW. as a result of which, system frequency dropped to 49.75 Hz. Further increase in load in the system resulted in a frequency of 49.25 Hz. At this condition, the power in MW supplied by the generator is ________ (rounded off to 2 decimal places).Correct answer is '130'. Can you explain this answer?.
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