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Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer?.

Solutions for Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE. Download more important topics, notes, lectures and mock test series for GATE Exam by signing up for free.

Here you can find the meaning of Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer?, a detailed solution for Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer? has been provided alongside types of Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer? tests, examples and also practice GATE tests.