Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer?

Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity

Open App

GATE Exam > GATE Questions > Bus 1 with voltage magnitude V1 = 1.1 p.u. is...

Join the Discussion on the App

Bus 1 with voltage magnitude V₁ = 1.1 p.u. is sending reactive power Q₁₂ towards bus 2 with voltage magnitude V₂ = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q₁₂ sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V₁, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .

Correct answer is '1.12'. Can you explain this answer?

FREE This question is part of

Test: GATE Electrical Engineering (EE) Previous Paper 2020

Attempt Test

Attempt this Test

Verified Answer

Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q...

With real power zero, load angle δ = 0
With initial values, V₁ = 1.1, V₂ = 1

With increased value of voltage,
new value of Q₁₂ = 1.2Q₁₂, V₂ = 1

V²₁ −V₁− 0.132 =0
V₁= 1.12, –0.118
Hence the practical value in per unit, V₁ = 1.12 p.u.

View all questions of this test

View all answers Start learning for free

< Previous Question Next Question >

Explore Courses for GATE exam

Similar GATE Doubts

A three phase load of 3000 kVA, 0.8 p.f. is supplied at 11kV from a step-down transformer having a ratio 3:1. The primary side of transformer is connected to a transmision line, the constant s of which are resistance per conductor, 2 ohms, reactance per conducter, 3 ohms. T he resistance and reactance per phase of the primary windings of the transformer (which are star connecte d) are 5 and 10 respectively, and the corresponding value for the secondary winding (which are delta connected) are 1.5 ohms and 3 ohms respectively. The voltage and power factor at the sending end of the transmission line is

View answer

A synchronous generator is connected to an infinite bus with excitation voltage Ef = 1.3 pu. The generator has a synchronous reactance of 1.1 pu and is delivering real power (P) of 0.6 pu to the bus. Assume the infinite bus voltage to be 1.0 pu. Neglect stator resistance. The reactive power (Q) in pu supplied by the generator to the bus under this condition is _________. Correct answer is '0.109'. Can you explain this answer?

View answer

A cylindrical rotor synchronous generator has steady state synchronous reactance of 0.7 pu and subtransient reactance of 0.2 pu. It is operating at (1+ j0) pu terminal voltage with an internal emf of (1 + j0.7) pu. Following a three-phase solid short circuit fault at the terminal of the generator, the magnitude of the subtransient internal emf (rounded off to 2 decimal places) is ________ pu. Correct answer is '1.02'. Can you explain this answer?

View answer

The positive, negative and zero sequence reactances of a wye-connected synchronous generator are 0.2 pu, 0.2 pu, and 0.1 pu, respectively. The generator is on open circuit with a terminal voltage of 1 pu. The minimum value of the inductive reactance, in pu, required to be connected between neutral and ground so that the fault current does not exceed 3.75 pu if a single line to ground fault occurs at the terminals is _______ (assume fault impedance to be zero). Correct answer is between '0.1,0.1'. Can you explain this answer?

View answer

A 30 MVA 3-phase, 50Hz, 13.8 kV, star-connected synchronous generator has positive, negative and zero sequence reactances, 15%, 15% and 5% respectively. A reactance (Xn) is connected between the neutral of the generator and ground. A double line to ground fault takes place involving phases ‘b’ and ‘c’, with a fault impedance of j0.1 p.u. The value of Xn (in p.u) that will limit the positive sequence current to 4270 A is _____________. Correct answer is '1.1'. Can you explain this answer?

View answer

Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer?

Share with a Friend

Answer this doubt

Question Description
Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer?.

Solutions for Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE. Download more important topics, notes, lectures and mock test series for GATE Exam by signing up for free.

Here you can find the meaning of Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer?, a detailed solution for Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer? has been provided alongside types of Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Bus 1 with voltage magnitude V1 = 1.1 p.u. is sending reactive power Q12 towards bus 2 with voltage magnitude V2 = 1 p.u. through a lossless transmission line of reactance X. Keeping the voltage at bus 2 fixed at 1 p.u., magnitude of voltage at bus 1 is changed, so that the reactive power Q12 sent from bus 1 is increased by 20%. Real power flow through the line under both the conditions is zero. The new value of the voltage magnitude, V1, in p.u. (rounded off to 2 decimal places) at bus 1 is _______ .Correct answer is '1.12'. Can you explain this answer? tests, examples and also practice GATE tests.

Explore Courses for GATE exam