A cylindrical bar with 200 mm diameter is being turned with a tool having geometry 0anddeg; - 9anddeg; - 7anddeg; - 8anddeg; - 15anddeg; - 30anddeg; - 0.05 inch (Coordinate system, ASA) resulting in a cutting force Fc1. If the tool geometry is changed to 0anddeg; - 9anddeg; - 7anddeg; - 8anddeg; - 15anddeg; - 0anddeg; - 0.05 inch (Coordinate system. ASA) and all other parameters remain unchanged, the cutting force changes to Fc2. Specific cutting energy (in J/mm3) is Uc = U0 (t1)andndash;0.4, where U0 is the specific energy coefficient, and t1 is the uncut thickness in mm. The value of percentage change in cutting force Fc2. i.e.,x100, is _______ (round off to one decimal place).Correct answer is '-5.6'. Can you explain this answer?

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A cylindrical bar with 200 mm diameter is being turned with a tool having geometry 0° - 9° - 7° - 8° - 15° - 30° - 0.05 inch (Coordinate system, ASA) resulting in a cutting force F_c1. If the tool geometry is changed to 0° - 9° - 7° - 8° - 15° - 0° - 0.05 inch (Coordinate system. ASA) and all other parameters remain unchanged, the cutting force changes to F_c2. Specific cutting energy (in J/mm³) is U_c = U₀ (t₁)^–0.4, where U₀ is the specific energy coefficient, and t₁ is the uncut thickness in mm. The value of percentage change in cutting force F_c2. i.e.,

x 100 , is _______ (round off to one decimal place).

Correct answer is '-5.6'. Can you explain this answer?

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A cylindrical bar with 200 mm diameter is being turned with a tool hav...

C_s1 = 30°
∴ λ₁ = 90 – 30 = 60°
Cs₂ =0°
∴ λ₂ = 90 – 0 = 90°
We know that specific energy consumption

∴ F_c = U₀(fsinλ)^−0.4× 1000fd
∴ F_c ∝ (sin λ)^–0.4
∴

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A cylindrical bar with 200 mm diameter is being turned with a tool having geometry 0° - 9° - 7° - 8° - 15° - 30° - 0.05 inch (Coordinate system, ASA) resulting in a cutting force Fc1. If the tool geometry is changed to 0° - 9° - 7° - 8° - 15° - 0° - 0.05 inch (Coordinate system. ASA) and all other parameters remain unchanged, the cutting force changes to Fc2. Specific cutting energy (in J/mm3) is Uc = U0 (t1)–0.4, where U0 is the specific energy coefficient, and t1 is the uncut thickness in mm. The value of percentage change in cutting force Fc2. i.e.,x100, is _______ (round off to one decimal place).Correct answer is '-5.6'. Can you explain this answer?

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A cylindrical bar with 200 mm diameter is being turned with a tool having geometry 0° - 9° - 7° - 8° - 15° - 30° - 0.05 inch (Coordinate system, ASA) resulting in a cutting force Fc1. If the tool geometry is changed to 0° - 9° - 7° - 8° - 15° - 0° - 0.05 inch (Coordinate system. ASA) and all other parameters remain unchanged, the cutting force changes to Fc2. Specific cutting energy (in J/mm3) is Uc = U0 (t1)–0.4, where U0 is the specific energy coefficient, and t1 is the uncut thickness in mm. The value of percentage change in cutting force Fc2. i.e.,x100, is _______ (round off to one decimal place).Correct answer is '-5.6'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A cylindrical bar with 200 mm diameter is being turned with a tool having geometry 0° - 9° - 7° - 8° - 15° - 30° - 0.05 inch (Coordinate system, ASA) resulting in a cutting force Fc1. If the tool geometry is changed to 0° - 9° - 7° - 8° - 15° - 0° - 0.05 inch (Coordinate system. ASA) and all other parameters remain unchanged, the cutting force changes to Fc2. Specific cutting energy (in J/mm3) is Uc = U0 (t1)–0.4, where U0 is the specific energy coefficient, and t1 is the uncut thickness in mm. The value of percentage change in cutting force Fc2. i.e.,x100, is _______ (round off to one decimal place).Correct answer is '-5.6'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cylindrical bar with 200 mm diameter is being turned with a tool having geometry 0° - 9° - 7° - 8° - 15° - 30° - 0.05 inch (Coordinate system, ASA) resulting in a cutting force Fc1. If the tool geometry is changed to 0° - 9° - 7° - 8° - 15° - 0° - 0.05 inch (Coordinate system. ASA) and all other parameters remain unchanged, the cutting force changes to Fc2. Specific cutting energy (in J/mm3) is Uc = U0 (t1)–0.4, where U0 is the specific energy coefficient, and t1 is the uncut thickness in mm. The value of percentage change in cutting force Fc2. i.e.,x100, is _______ (round off to one decimal place).Correct answer is '-5.6'. Can you explain this answer?.

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