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Keeping all other parameters identical, the Compression Ratio (CR) of an air standard diesel cycle is increased from 15 to 21. Take ratio of specific heats = 1.3 and cut-off ratio of the cycle rc = 2.
The difference between the new and the old efficiency values, in percentage,
(round off to one decimal place).
    Correct answer is '4.8'. Can you explain this answer?
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    Keeping all other parameters identical, the Compression Ratio (CR) of ...


    ηd, r=21 – ηd, r=15 =4.8%
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    Keeping all other parameters identical, the Compression Ratio (CR) of an air standard diesel cycle is increased from 15 to 21. Take ratio of specific heats = 1.3 and cut-off ratio of the cycle rc = 2.The difference between the new and the old efficiency values, in percentage,(round off to one decimal place).Correct answer is '4.8'. Can you explain this answer?
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    Keeping all other parameters identical, the Compression Ratio (CR) of an air standard diesel cycle is increased from 15 to 21. Take ratio of specific heats = 1.3 and cut-off ratio of the cycle rc = 2.The difference between the new and the old efficiency values, in percentage,(round off to one decimal place).Correct answer is '4.8'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about Keeping all other parameters identical, the Compression Ratio (CR) of an air standard diesel cycle is increased from 15 to 21. Take ratio of specific heats = 1.3 and cut-off ratio of the cycle rc = 2.The difference between the new and the old efficiency values, in percentage,(round off to one decimal place).Correct answer is '4.8'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Keeping all other parameters identical, the Compression Ratio (CR) of an air standard diesel cycle is increased from 15 to 21. Take ratio of specific heats = 1.3 and cut-off ratio of the cycle rc = 2.The difference between the new and the old efficiency values, in percentage,(round off to one decimal place).Correct answer is '4.8'. Can you explain this answer?.
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