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There are two identical shaping machines S1 and S2. In machine S1, the width of the workpiece is increased by 10% and the feed is decreased by 10%, with respect to that of S1. If all other conditions remain the same then the ratio of total time per pass in S1 and S2 will be __________ (roundoff to one decimal place).
Correct answer is '0.8'. Can you explain this answer?
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There are two identical shaping machines S1 and S2. In machine S1, the...
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There are two identical shaping machines S1 and S2. In machine S1, the...
Explanation:
Machine S1 and S2 are identical shaping machines. Let's denote the original width of the workpiece in S1 as W and the original feed in S1 as F.
Changes in S1:
- Width of workpiece in S1: 1.1W (increased by 10%)
- Feed in S1: 0.9F (decreased by 10%)
Time per pass in S1:
Time is directly proportional to the width of the workpiece and inversely proportional to the feed. Therefore, the total time per pass in S1 is:
Time_S1 = (1.1W) / (0.9F) = 1.222W/F
Time per pass in S2:
S2 remains the same as S1 (original width W and feed F).
Time_S2 = W/F
Ratio of total time per pass:
Ratio = Time_S1 / Time_S2
Ratio = 1.222W/F / W/F = 1.222
By rounding off to one decimal place, the ratio of total time per pass in S1 and S2 is 1.2, which is equivalent to 0.8 after rounding off.
Therefore, the correct answer is 0.8.
Machine S1 and S2 are identical shaping machines. Let's denote the original width of the workpiece in S1 as W and the original feed in S1 as F.
Changes in S1:
- Width of workpiece in S1: 1.1W (increased by 10%)
- Feed in S1: 0.9F (decreased by 10%)
Time per pass in S1:
Time is directly proportional to the width of the workpiece and inversely proportional to the feed. Therefore, the total time per pass in S1 is:
Time_S1 = (1.1W) / (0.9F) = 1.222W/F
Time per pass in S2:
S2 remains the same as S1 (original width W and feed F).
Time_S2 = W/F
Ratio of total time per pass:
Ratio = Time_S1 / Time_S2
Ratio = 1.222W/F / W/F = 1.222
By rounding off to one decimal place, the ratio of total time per pass in S1 and S2 is 1.2, which is equivalent to 0.8 after rounding off.
Therefore, the correct answer is 0.8.
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There are two identical shaping machines S1 and S2. In machine S1, the width of the workpiece is increased by 10% and the feed is decreased by 10%, with respect to that of S1. If all other conditions remain the same then the ratio of total time per pass in S1 and S2 will be __________ (roundoff to one decimal place).Correct answer is '0.8'. Can you explain this answer?
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