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The function f (z ) of complex variable z = x + iy , where i = −1 , is given as f (z ) = (x3 – 3xy2) + iv (x, y ). For this function to be analytic, v (x, y ) should be
  • a)
    (3x2y – y3) + constant
  • b)
    (3x2y2 – y3) + constant
  • c)
    (x2 – 3x2y) + constant
  • d)
    (3xy2 – y3) + constant
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The function f (z ) of complex variable z = x + iy , where i = −...
f (z)= u + iv
u = x3 – 3 xy2, v = v (x, y )
For f (z ) to be Analytical,
ux =3x2 – 3y2 = vy
uy =–6 xy = –vx
vx =6 xy by integrating w.r.t x ⇒ v = 3x2y + C1
vy =3x2 – 3y2 by integrating w.r.t y ⇒ v = 3x2y – y3 + C2
v =(3x2y – y3) + constant (C1 = –y3)
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Most Upvoted Answer
The function f (z ) of complex variable z = x + iy , where i = −...
The function f(z) of complex variable z = x + iy, where i = √(-1), is a function that maps a complex number z to another complex number. It can be written as f(z) = u + iv, where u and v are real-valued functions of x and y.

For example, let's say f(z) = z^2. In this case, we have f(z) = (x + iy)^2 = x^2 + 2ixy - y^2. So, u(x, y) = x^2 - y^2 and v(x, y) = 2xy.

Another example could be f(z) = e^z. In this case, we have f(z) = e^(x + iy) = e^x * e^(iy) = e^x * (cos(y) + i*sin(y)). So, u(x, y) = e^x * cos(y) and v(x, y) = e^x * sin(y).

The function f(z) can have various other forms depending on the specific function being considered. It can be a polynomial, exponential, logarithmic, trigonometric, or any other type of function. The specific form of f(z) will determine the behavior and properties of the function.
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The function f (z ) of complex variable z = x + iy , where i = −1 , is given as f (z ) = (x3 – 3xy2) + iv (x, y ). For this function to be analytic, v (x, y ) should bea)(3x2y – y3) + constantb)(3x2y2 – y3) + constantc)(x2 – 3x2y) + constantd)(3xy2 – y3) + constantCorrect answer is option 'A'. Can you explain this answer?
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