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The following data applies to basic shaft system: tolerance for hole = 0.002 mm, tolerance for shaft = 0.001 mm, allowance = 0.003 mm, basic size = 50 mm The maximum hole size is ______ mm (round off to 3 decimal places).
    Correct answer is '50.005'. Can you explain this answer?
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    The following data applies to basic shaft system: tolerance for hole =...
    Using diagram method

    UL of hole = BS + 0.003 + 0.002 mm = 50.005 mm
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    The following data applies to basic shaft system: tolerance for hole =...
    Calculation of Maximum Hole Size in Basic Shaft System

    Given Data:

    • Tolerance for hole = 0.002 mm

    • Tolerance for shaft = 0.001 mm

    • Allowance = 0.003 mm

    • Basic size = 50 mm



    Formula:
    Maximum Hole Size = Basic Size + Allowance + Tolerance for Hole

    Calculation:
    Maximum Hole Size = 50 + 0.003 + 0.002 = 50.005 mm

    Therefore, the maximum hole size in the basic shaft system is 50.005 mm.

    Explanation:

    • The basic size is the nominal size of the shaft or hole.

    • The allowance is the intentional difference between the maximum shaft size and the minimum hole size.

    • The tolerance is the permissible variation in the size of the shaft or hole.

    • The maximum hole size is calculated by adding the basic size, allowance, and tolerance for the hole.

    • In this case, the maximum hole size is 50.005 mm, which means that the hole can have a size of up to 50.005 mm without affecting the function of the system.

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    The following data applies to basic shaft system: tolerance for hole = 0.002 mm, tolerance for shaft = 0.001 mm, allowance = 0.003 mm, basic size = 50 mm The maximum hole size is ______ mm (round off to 3 decimal places).Correct answer is '50.005'. Can you explain this answer?
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