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X-rays of wKa (wavelength 154 pm) are diffracted by a set of atomic planes in a crystals in the following manner. The separation of the la yers in the crystals in 404 Pm. Find the angle a along which the first order reflection will occur:?
Most Upvoted Answer
X-rays of wKa (wavelength 154 pm) are diffracted by a set of atomic pl...
This is based on Bragg's equation which is given by

order of reflection×wavelength = 2(distance between the layers)(sinx)

.:here, x refers angle

the answer is 10.98degrees
Community Answer
X-rays of wKa (wavelength 154 pm) are diffracted by a set of atomic pl...
Introduction:
In this problem, we are given the wavelength (λ) of X-rays (154 pm) and the separation between the layers (d) in a crystal (404 pm). We need to find the angle (θ) at which the first-order reflection will occur.

Formula:
The formula to calculate the angle of reflection for a diffraction pattern is given by Bragg's Law:
nλ = 2d sin(θ)

where:
n is the order of reflection (in this case, it is 1),
λ is the wavelength of the X-rays,
d is the separation between the layers in the crystal, and
θ is the angle of reflection.

Calculation:
Using Bragg's Law, we can rearrange the formula to solve for θ:
sin(θ) = (nλ) / (2d)

Substituting the given values:
sin(θ) = (1 * 154 pm) / (2 * 404 pm)

Now, let's convert the values to meters for convenience:
sin(θ) = (1 * 154 * 10^(-12) m) / (2 * 404 * 10^(-12) m)

Cancelling out the units:
sin(θ) = 154 / 808

Calculating the value of sin(θ):
sin(θ) ≈ 0.1906

To find the value of θ, we take the inverse sine (sin^(-1)) of 0.1906:
θ ≈ sin^(-1)(0.1906)

Using a calculator, we find:
θ ≈ 11.04 degrees

Conclusion:
Therefore, the angle at which the first-order reflection will occur is approximately 11.04 degrees.
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X-rays of wKa (wavelength 154 pm) are diffracted by a set of atomic planes in a crystals in the following manner. The separation of the la yers in the crystals in 404 Pm. Find the angle a along which the first order reflection will occur:?
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