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Square blanks of 8 mm side lengths are blanked from an aluminium sheet of 3 mm thickness. The shear strength of the aluminium is 85 MPa. The minimum blanking force (in kN) is _________?
  • a)
    4.08
  • b)
    5.26
  • c)
    7.26
  • d)
    8.16
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Square blanks of 8 mm side lengths are blanked from an aluminium sheet...
To find the minimum blanking force, we need to consider the shear strength of the material and the area that needs to be sheared.

Given data:
Side length of square blanks = 8 mm
Thickness of aluminium sheet = 3 mm
Shear strength of aluminium = 85 MPa

1. Calculate the area of the square blanks:
The area of a square is given by the formula A = side length^2.
So, the area of each square blank is 8 mm * 8 mm = 64 mm^2.

2. Determine the shear area:
The shear area is the area of material that needs to be sheared.
The shear area is given by the formula As = thickness * perimeter.
The perimeter of a square is given by the formula P = 4 * side length.
So, the shear area is 3 mm * (4 * 8 mm) = 96 mm^2.

3. Calculate the minimum blanking force:
The minimum blanking force can be calculated using the formula F = shear strength * shear area.
Converting the shear strength from MPa to N/mm^2, we have 85 MPa = 85 N/mm^2.
So, the minimum blanking force is 85 N/mm^2 * 96 mm^2 = 8160 N = 8.16 kN.

Therefore, the minimum blanking force is 8.16 kN, which corresponds to option D.
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Square blanks of 8 mm side lengths are blanked from an aluminium sheet of 3 mm thickness. The shear strength of the aluminium is 85 MPa. The minimum blanking force (in kN) is _________?a)4.08b)5.26c)7.26d)8.16Correct answer is option 'D'. Can you explain this answer?
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