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In Young's double slit experiment, the fringe width is found to be 0.4 mm. If the whole apparatus is immersed in water of refractive index 4/3 without disturbing the geometrical arrangement, the new fringe width will be
  • a)
    0.30 mm
  • b)
    0.40 mm
  • c)
    0.53 mm
  • d)
    0.50 mm
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
In Young's double slit experiment, the fringe width is found to be 0.4...
Solution:

Given, fringe width in air, δ = 0.4 mm

Refractive index of water, μ = 4/3

We know that, fringe width in a medium is given by the formula:

δ' = δ/μ

Substituting the given values, we get:

δ' = 0.4 mm / (4/3) = 0.3 mm

Therefore, the new fringe width when the whole apparatus is immersed in water without disturbing the geometrical arrangement is 0.3 mm.

Answer: (a) 0.30 mm
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In Young's double slit experiment, the fringe width is found to be 0.4...
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In Young's double slit experiment, the fringe width is found to be 0.4 mm. If the whole apparatus is immersed in water of refractive index 4/3 without disturbing the geometrical arrangement, the new fringe width will bea)0.30 mmb) 0.40 mmc) 0.53 mmd) 0.50 mmCorrect answer is option 'A'. Can you explain this answer?
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